如何使用php sql查询使事件显示在日历中？

Question

Edit* I have found the issue. The date is being converted to this format: Mar 1 2018 12:00AM I have posted my solution below.

My query returns the appropriate results, however none of the events are showing up on the calendar.

Here's what the data looks like in SQL in case there's format issues I don't know about:

Name: Test

Start: 2009-09-23 00:00:00.000

End: 2010-04-05 00:00:00.000

PHP:

$query = mssql_query("select [NAME], [Start], [End] from [database] where [Name] = 'Test'");

       $result = array();

        if (mssql_num_rows($query)) {

            while ($row = mssql_fetch_assoc($query)) {

                $result[] = $row;
            }
        } 

        $data = array();

        foreach($result as $i => $item)
        {
         $data[] = array(
          'title'   => $item["Name"],
          'start'   => $item["Start"],
          'end'   => $item["End"]
         );
        }

JSON/JS:

<script type="text/javascript">
 $(document).ready(function() {
 var calendar = $('#calendar').fullCalendar({
 editable:true,
 header:{
 left: 'prev,next today',
  center: 'title',
  right: 'month,agendaWeek,agendaDay,listMonth'
},
events: <?php echo json_encode($data); ?> ,
selectable:true,
selectHelper:true,

})

});
</script>

Answer 1

For some reason my date format was being converted, so I just converted it in the php loop:

<?php
foreach($result as $i => $item)
    {
     $data[] = array(
      'title'   => $item["Name"],
      'start'   => date("Y-m-d", strtotime($item["Start"]));
      'end'   => date("Y-m-d", strtotime($item["End"]));
     );
    }
?>