[英]BASH copy specific lines from terminal
Let's say currently my terminal looks like the following: 假设当前我的终端如下所示:
neekoy@mypc:~/some/folder$ echo "lala nana"
lala nana
neekoy@mypc:~/some/folder$ l
entrypoint.js helpers/ node_modules/ package.json package-lock.json
neekoy@mypc:~/some/folder$
I want to copy the fourth line from the bottom (the one that contains "lala nana"). 我要从底部复制第四行(包含“ lala nana”的那一行)。
I can obviously write a script that uses tput to save the cursor position, switch my cursor's position to a specific line, copy it, and then return to the previous cursor position. 我显然可以编写一个脚本,使用tput保存光标位置,将光标的位置切换到特定行,复制它,然后返回到先前的光标位置。
Is there an existent solution or an easier way to accomplish this though? 是否有一个现有的解决方案或更简单的方法来完成此任务?
I'm not sure I understand your problem. 我不确定我是否理解您的问题。 I would solve it this way, though.
我会这样解决的。
I would put the command into a variable to access it again later. 我会将命令放入变量中,以便稍后再次访问。 ( http://www.tldp.org/LDP/abs/html/varassignment.html )
( http://www.tldp.org/LDP/abs/html/varassignment.html )
Here is an example: 这是一个例子:
neekoy@mypc:~/some/folder$ c=$(echo "lala nana")
neekoy@mypc:~/some/folder$ echo $c
lala nana
Or like in your example: 或像您的示例所示:
neekoy@mypc:~/some/folder$ echo "lala nana"
lala nana
neekoy@mypc:~/some/folder$ l
entrypoint.js helpers/ node_modules/ package.json package-lock.json
neekoy@mypc:~/some/folder$ c=$(!-2) #related to https://unix.stackexchange.com/a/33552
neekoy@mypc:~/some/folder$ echo $c
lala nana
Or save the output as text in a file. 或将输出另存为文本文件。
neekoy@mypc:~/some/folder$ echo "lala nana"
lala nana
neekoy@mypc:~/some/folder$ l
entrypoint.js helpers/ node_modules/ package.json package-lock.json
neekoy@mypc:~/some/folder$ !-2 > test.txt
echo "lala nana" > test.txt
neekoy@mypc:~/some/folder$ cat test.txt
lala nana
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