在UI测试中执行完全向左滑动动作？

Question

I have implemented leading and trailing swipe actions in a table view. Now, I'm trying to test them in XCTest UI tests.

To test a regular swipe in either direction is easy:

tableCell.swipeRight()
tableCell.swipeLeft()

Using one of these causes the 1st action button to be displayed, and I can then .tap() on the button.

However, testing a full swipe is proving a little more challenging. I have played with this extension from How do I swipe faster or more precisely?

I have also played with this answer from the question Xcode7 ui testing: staticTexts[“XX”].swipeRight() swipes not far enough .

Both of these essentially use XCUIElement's coordinate(withNormalizedOffset:) method to swipe from one point to another, similar to the following:

let startPoint = tableCell.coordinate(withNormalizedOffset: CGVector.zero)
let finishPoint = startPoint.withOffset(CGVector(dx:xOffsetValue, dy:yOffsetValue))
startPoint.press(forDuration: 0, thenDragTo: finishPoint)

I ended up with an extension that successfully performs a full swipe right - but I can't seem to get the numbers right for a full swipe left .

My code does perform a swipe left, but just doesn't go far enough. I've tried hardcoded numbers for dx: from -300 to 300. The element width is 414. I believe that 0 is the far left, and 414 would be the far right, so I started using that size as a reference. Still, no joy.

How can I get this to perform a full swipe left?

extension XCUIElement
{
    enum SwipeDirection {
        case left, right
    }

    func longSwipe(_ direction : SwipeDirection) {
        let elementLength = self.frame.size.width
        let centerPoint: CGFloat = elementLength / 2.0
        let halfCenterValue: CGFloat = centerPoint / 2.0

        let startOffset: CGVector
        let endOffset: CGVector
        switch direction {
        case .right:  // this one works perfectly!
            startOffset = CGVector.zero
            endOffset = CGVector(dx: centerPoint + halfCenterValue, dy: 0)
        }
        case .left:  // "There's the rub" as Hamlet might say...
            startOffset = CGVector(dx: centerPoint + halfCenterValue, dy: 0)
            endOffset = CGVector.zero

        let startPoint = self.coordinate(withNormalizedOffset: startOffset)
        let finishPoint = startPoint.withOffset(endOffset)
        startPoint.press(forDuration: 0, thenDragTo: finishPoint)
    }
}

Answer 1

Got it!

• First, I didn't need to use the frame size of the cell. The "normalized" part means that you can use values from 0.0 to 1.0 to represent a percentage of an element's size.

• Second, playing with the sizes, I found a long swipe needs to move about 60% of the width of the cell in order to activate the action.

My resulting long swipe extension:

extension XCUIElement
{
    enum SwipeDirection {
        case left, right
    }

    func longSwipe(_ direction : SwipeDirection) {
        let startOffset: CGVector
        let endOffset: CGVector

        switch direction {
        case .right:
            startOffset = CGVector.zero
            endOffset = CGVector(dx: 0.6, dy: 0.0)
        case .left:
            startOffset = CGVector(dx: 0.6, dy: 0.0)
            endOffset = CGVector.zero
        }

        let startPoint = self.coordinate(withNormalizedOffset: startOffset)
        let endPoint = self.coordinate(withNormalizedOffset: endOffset)
        startPoint.press(forDuration: 0, thenDragTo: endPoint)
    }
}

Note: CGVector.zero is a Swift alias for CGVector(dx: 0.0, dy: 0.0)