[英]Append multiple excel file into one excel file by sheet in R
I have multiple excel files, and I just want to append them in single excel file based on the sheet (For example, Data of Sheet1 always append to sheet1 and so on for sheet2). 我有多个Excel文件,我只想基于工作表将它们追加到单个excel文件中(例如,工作表1的数据始终追加到工作表1上,对于工作表2依此类推)。
And i want to keep only one header of any one file, and while appending other files I want to remove the header column. 我只想保留任何一个文件的一个标头,而在附加其他文件时,我想删除标头列。
so far i have tried. 到目前为止,我已经尝试过了。
library(dplyr)
library(xlsx)
path<- "C:/Users/KJD14/Documents/Test - "
dataFolders<- list.files(path,pattern = "*.xlsx")
dataFolders<- sort(dataFolders[starts_with(match = "Test - ", vars = dataFolders)])
files<- lapply(lapply(dataFolders, FUN = function(x){
paste(path,x,sep = "/")
}), FUN = function(x){
list.files(x, pattern = "*.xlsx", full.names = TRUE)
})
Using this you can read in all the sheets of one excel file 使用此功能,您可以阅读一个excel文件的所有表格。
library(data.table)
library(readxl)
# Using the example excel file and only read in the first sheet three times
list.import <- lapply(rep(excel_sheets(readxl_example("datasets.xlsx"))[1],3), function(sheet){read_xlsx(readxl_example("datasets.xlsx"), sheet = sheet )})
dt <- rbindlist(list.import)
Using an additional loop you can then also read in more than one excel file if you like. 如果需要,还可以使用一个附加循环读取多个excel文件。 I just found a new package, which at the moment is only on github, but probably could be installed.
我刚刚找到了一个新软件包,该软件包目前仅在github上,但可能可以安装。 So please checkout: https://github.com/ropensci/writexl To install:
因此,请检出: https : //github.com/ropensci/writexl要安装:
install.packages("devtools")
library(devtools)
writexl::write_xlsx(dt, path = "temp.xlsx")
Please mind that I haven't checked the last lines of code if they work properly, so please test that on your own. 请注意,我没有检查最后几行代码是否正常工作,因此请自行进行测试。
Here's an option that returns a data frame with columns for file and sheet names for each file. 这是一个选项,它返回一个数据框,其中包含用于文件的列和用于每个文件的工作表名称。 In this example, not every file has the same sheets or columns;
在此示例中,并非每个文件都具有相同的工作表或列。 test2.xlsx has only one sheet and test3.xlsx sheet1 does not have col3.
test2.xlsx只有一张工作表,而test3.xlsx sheet1没有col3。
library(tidyverse)
library(readxl)
dir_path <- "~/test_dir/" # target directory where the xlsx files are located.
re_file <- "^test[0-9]\\.xlsx" # regex pattern to match the file name format, in this case 'test1.xlsx', 'test2.xlsx' etc.
read_sheets <- function(dir_path, file){
xlsx_file <- paste0(dir_path, file)
xlsx_file %>%
excel_sheets() %>%
set_names() %>%
map_df(read_excel, path = xlsx_file, .id = 'sheet_name') %>%
mutate(file_name = file) %>%
select(file_name, sheet_name, everything())
}
df <- list.files(dir_path, re_file) %>%
map_df(~ read_sheets(dir_path, .))
# A tibble: 15 x 5
file_name sheet_name col1 col2 col3
<chr> <chr> <dbl> <dbl> <dbl>
1 test1.xlsx Sheet1 1 2 4
2 test1.xlsx Sheet1 3 2 3
3 test1.xlsx Sheet1 2 4 4
4 test1.xlsx Sheet2 3 3 1
5 test1.xlsx Sheet2 2 2 2
6 test1.xlsx Sheet2 4 3 4
7 test2.xlsx Sheet1 1 3 5
8 test2.xlsx Sheet1 4 4 3
9 test2.xlsx Sheet1 1 2 2
10 test3.xlsx Sheet1 3 9 NA
11 test3.xlsx Sheet1 4 7 NA
12 test3.xlsx Sheet1 5 3 NA
13 test3.xlsx Sheet2 1 3 4
14 test3.xlsx Sheet2 2 5 9
15 test3.xlsx Sheet2 4 3 1
And then exporting to a single XLSX file: 然后导出到单个XLSX文件:
library(xlsx)
write.xlsx(df, 'file_name.xslx', sheetName="Sheet1", row.names=TRUE)
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