通过Curl将JSON编码为PHP变量失败，响应为空
[英]JSON Encode To PHP Variable via Curl fails with empty response
问题描述
i have searched a lot on google and here but im not getting any further with my problem. 
我已经在Google和此处进行了大量搜索，但是我的问题没有得到进一步解决。 I am not a coder though I am trying to parse JSON to PHP Variables, but i get an empty response, where i want a table to be shown or at least any jsondata 虽然我尝试将JSON解析为PHP变量，但我不是编码员，但是我得到一个空响应，在此我希望显示一个表或至少显示任何jsondata
Here is what my code looks like: 这是我的代码：
<!DOCTYPE html>
<html>
<body>
<h1>Available Agents </h1>
<?php
$url = 'https://url/livewebservice/imoscontactagentstate?Username=username&Pwd=password&Cmd=GetState&ResultType=JSON';
// Initiate curl
$ch = curl_init ($url);
$data = json_encode ($data,true);
curl_setopt ($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt ($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt ($ch, CURLOPT_HTTPHEADER, array (
' Content-Type: application/x-www-form-urlencoded ',
'charset=utf-8')
);
$result = curl_exec ($ch);
curl_close ($ch);
return $result;
var_dump(json_decode($result, true));
print_r($result);
foreach ($result as $key => $value)
{
echo ' <td><font face="calibri"color="red">'.$value[type].' </font></td><td><font face="calibri"color="blue">'.$value[category].' </font></td><td><font face="calibri"color="green">'.$value[amount].' </font></tr><tr>';
}
echo "</tr></table>";
?>
</body>
</html>
I am grateful for any hints 我很感谢任何提示
2 个解决方案
解决方案1
0 2018-08-02 20:12:05
Try to remove true from $data = json_encode ($data,true); 尝试从$data = json_encode ($data,true);删除true $data = json_encode ($data,true); as far as can i remember true is used only in json_decode to create an associative array 据我所记得， true仅在json_decode中使用以创建关联数组
解决方案2
0 已采纳 2018-08-04 06:14:08
The problem was solved my Username did not have the permission to access the data and we made minor changes to the code so it looks like this: 问题已解决，我的用户名没有访问数据的权限，并且我们对代码进行了细微更改，因此看起来像这样：
php $data = array( "UserName" => "Username", "Pwd" => "Password", "Cmd" => "GetAgentStateList", "ResultType" => "JSON", ); $url='https://host/livewebservice/service/?'.http_build_query($data); echo $url; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HTTPHEADER, array( "Content-Type: application/x-www-form-urlencoded", "charset=UTF-8",)); $result = curl_exec($ch); if(curl_errno($ch)){ throw new Exception(curl_error($ch)); } curl_close($ch); $f_result=json_decode($result); print_r($f_result); ?>
i hope this helps someone coming from google someday. 我希望这可以帮助某天来自Google的人。
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