DataContractSerializer-如何使用ElementName而不是属性名称序列化对象？

Question

I'm facing serialization issue while using DataContractSerializer . The issue I'm facing is that the generated XML file always have the tags with names defined for the class and fields instead of the names set in XmlRoot or XmlElement using ElementName attribute. eg For the class defined as follows:

[XmlRoot(ElementName = "customer")]
public class Customer
{
    [XmlElement(ElementName = "name")]
    public string Name { get; set; }
    [XmlElement(ElementName = "address")]
    public string Address { get; set; }
}

The generated XML in my case is always:

<Customer>
    <Name>abc</Name>
    <Address>xyz</Address>
</Customer>

while the output I'm looking to get is the one using ElementName in lowercase:

<customer>
    <name>abc</name>
    <address>xyz</address>
</customer>

I'm using an extension method to serialize by C# object using the following:

public static XDocument SerializeToXElement(object o)
{
    XDocument doc = new XDocument();

    using (var writer = doc.CreateWriter())
    {
        var serializer = new DataContractSerializer(o.GetType());
        XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
        ns.Add("", "");
        serializer.WriteObject(writer, o);
    }

    doc.StripNamespace();

    return doc;
}

I also have another extension method being called in my serialize function to strip the namespaces out from my XDocument , which is as follows:

public static void StripNamespace(this XDocument document)
{
    if (document.Root == null) return;

    foreach (var element in document.Root.DescendantsAndSelf())
    {
        element.Name = element.Name.LocalName;
        element.ReplaceAttributes(GetAttributesWithoutNamespace(element));
    }
}

What can I do to make the DataContractSerializer use ElementName instead of the class/property names?

Answer 1

This should work for you,

[XmlRoot("customer")]
public class Customer
{
    [XmlElement("name")]
    public string Name { get; set; }
    [XmlElement("address")]
    public string Address { get; set; }
}

Answer 2

As per my comment, you should use DataContract and DataMember attributes instead of XmlRoot and XmlElement :

[DataContract(Name = "customer", Namespace = "")]
public class Customer
{
    [DataMember(Name = "name")]
    public string Name { get; set; }

    [DataMember(Name = "address")]
    public string Address { get; set; }
}