C ++：是否可以为类型名建立模板？

Question

Suppose I write:

template<typename X>
typename Namespace::Something<X> S;

And then I template a function as follows:

template<typename X>
void my_function(X input){
    S<X> y = S<X>(input);
}

Is this possible? What would be the syntax to do it if it is possible?

Answer 1

You can use an alias template declaration :

template <typename X>
using S = Namespace::Something<X>;