PHP调用Javascript函数不接受参数

Question

Javascript:

function clickedLink(l){
     alert(l);
}

PHP:

If I don't pass in a parameter, like this. It returns undefined, which is correct.

echo '<tr class='.$class.' onclick="clickedLink();">;

If I try to pass a parameter in nothing happens.

  echo '<tr class='.$class.' onclick="clickedLink("test");">';
  echo '<tr class='.$class.' onclick="clickedLink(\"test\");">';
  echo '<tr class='.$class.' onclick="clickedLink('.$test.');">';

Any idea on why it's not working? It might be me not understanding how to access Javascript parameters inside the function.

Answer 1

Try adding \\' like this

clickedLink(\\'.$test.\\')