[英]Find a word in char array java
I'm trying to find a word from a dictonary list . 我试图从字典中找到一个词。 The letters can be in any order, but any letter can be used only once. 字母可以按任何顺序排列,但是任何字母只能使用一次。 I already developed an algorithm in java on Android, but it doesn't really work. 我已经在Android上的Java中开发了一种算法,但实际上并没有用。 --> all words in the dict list are already lowercased in my cause ->我的原因是字典列表中的所有单词都已经小写
Here is my existing code, but it won't show me the matching words as output, the returned list is always empty. 这是我现有的代码,但是不会显示匹配的单词作为输出,返回的列表始终为空。
private int matches = 0;
private ArrayList<String> words;
private ArrayList<String> check(String charArr0) {
String charArr = charArr0.toLowerCase();
char[] cs0 = charArr.toCharArray();
ArrayList<Character> cs = new ArrayList<>();
for(char c : cs0)
cs.add(c);
all = words.size();
ArrayList<String> out = new ArrayList<>();
for(String w0 : words) {
String w = w0.toLowerCase();
int len = w.length();
if(len >= 2) {
//only if len is 2++
matches = 0;
checkNext(cs, 0, w, len);
//if matches are as high as words lenght, it is fully avaivable
if(matches >= len)
out.add(w);
}
}
return out;
}
private void checkNext(ArrayList<Character> cs, int pos, String w, int len) {
if(pos < len) {
char twc = w.charAt(pos);
boolean cont = false;
int cIdx = -1, curi = 0;
for(char c : cs) {
if(c == twc){
cont = true;
cIdx = curi;
break;
}
curi += 1;
}
if(cont) {
matches += 1;
cs.remove(cIdx);
checkNext(cs, pos + 1, w, len);
}
}
}
The question is, what the error in this code is and how could I possibly get a word from the list in a char array given (any char only used once, order doesn't matter)? 问题是,此代码中的错误是什么?如何才能从给定的char数组(任何char只使用一次,顺序无关紧要)的列表中得到一个单词?
Because you define this rules : 因为您定义了以下规则:
//- The letters can be in any order
//- any letter can be used only once
I would like to sort the character of each word and check if they are equals or not : 我想对每个单词的字符进行排序 ,然后检查它们是否相等:
List<String> dictionaryWords = ...;
String word = "word";
char[] wordChars = word.toCharArray();
Arrays.sort(wordChars);
List<String> foundWords = new ArrayList<>();
for(String w : dictionaryWords){
if(dictionaryWords.length() != wordChars.length)
continue;
char[] wordDictionaryChars = w.toCharArray();
Arrays.sort(wordDictionaryChars);
if(Arrays.equals(wordChars, wordDictionaryChars)){
foundWords.add(w);
}
}
Consider you have : 考虑您有:
List<String> dictionaryWords = new ArrayList<>(Arrays.asList("drow", "hello"));
This will return : 这将返回:
[drow]
because when you order both word
and drow
it will gives you [d, o, r, w]
因为当您同时订购word
和drow
,它将给您[d, o, r, w]
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