分割逗号分隔的字符串并存储到变量中

Question

I want to split a string and store every data to variable in C#. How can I achieve that ?

My code is:

string name="John,Hutkins,Doe,San Francisco CA";

Output should be this:

string fname = "John";
string mname = "Hutkins";
string lname = "Doe";
string address= "San Francisco CA";

Answer 1

Its as simple as :

var results = name.Split(',');

if(results.Length != 4)
 throw new InvalidOperationException("Oh Noes!!!");

string fname = results[0];
string mname =  results[1];
string lname =  results[2];
string address=  results[3];

---

Warning the second you have a comma in your address, this is going to fail.

If this is a CSV file, consider using a dedicated CSV Parser, there are plenty

Further reading

String.Split Method

Returns a string array that contains the substrings in this instance that are delimited by elements of a specified string or Unicode character array.

Answer 2

Looks like the case where it is better having a class

public class PersonalInfo 
{

    public FName { get; private set; }
    public LName { get; private set; }
    public MName { get; private set; }
    public Address { get; private set; }

    public PersonalInfo (string info)
    {
        string[] items = info.Split(',');
        FName = items [0];
        MName = items [1];
        LName = items [2];
        Address = items [3];

    }

    public override ToString()
    {
       // return $"{LName}, {FName} {MName}"; // vs 2017
       return string.Format("{0}, {1} {2}", LName, FName, MName); // vs 2008
    }


}

Now you can actually use your objects in lists etc.

var pi = new PersonalInfo("John,Hutkins,Doe,San Francisco CA");
textBox1.Text = pi.FName;
. . . . . . . 

Answer 3

If this string is from .csv file consider using an available csv parser. Any way you can use this methid as well.

String [] results = name.Split(',');

In here your names will be stored in the results array. The index order will be the names order in the string starting with 0; Like this

String address = results[3];

But there is a mistake here. Since you are using the comma to separate the values you cannot use Commas in the address which will be hard. Try using something like '|' od '*'.

Regards