ls -l->按正则表达式对文件排序

Question

I have a directory with log-Files from different applications which are named like:

A_B_C.log.20180205125615.bin
A_B_C.log.20180205125616
A_B_C_20180205133700.log
A_B_C_1234_20180205133700.log
D_E_F_G.log.20180205125715.bin
D_E_F_G.log.20180205125716
D_E_F_G_20180205133800.log
D_E_F_G_1234_20180205133800.log

The names all contain a timestamp with 14 digits (year, month, day, time).

I would like to print all filenames by "ls -l" and order them by the timestamp in the name.

The newes Files (highest number) should be printet at the end. If ther are multiple matches for a timestamt, these files should be sorted in alphabetical order.

How can i combine "ls -l" with regex sorting?

Answer 1

Perl solution:

perl -le 'print for sort { ($a =~ /\d{14}/g)[0] cmp ($b =~ /\d{14}/g)[0]
                           or $a cmp $b } glob "*log*"'

See sort for details on how to provide custom comparators in Perl.

• -l adds final newlines to printed lines
• \\d{14} matches 14 digits
• matching with the /g modifier returns the matching substrings in list context, [0] selects the first of them.

Answer 2

This line with gnu sed should help:

ls -1|sed -r 's/.*([0-9]{14}).*/\1 &/' f|sort -n|sed 's/^[0-9]* //' 

Ls cannot do it on its own. The idea is: take the timestamp out, to the head of each line as key, then sort by timestamp, finally remove the inserted timestamp.