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在spring boot中连接到多个数据库

[英]Connecting to multiple database in spring boot

I need to connect to two database in my project. 我需要连接到我的项目中的两个数据库。 So I created two configuration files. 所以我创建了两个配置文件。

@Configuration
@EnableTransactionManagement
@EnableJpaRepositories( basePackages = {"com.virat.webservices.datastore.v1.Repo" } )
@EntityScan("com.virat.webservices.datastore.v1.Model")
public class V1DBConfig {

@Primary
@Bean( name = "dataSource" )
@ConfigurationProperties( prefix = "v1.datasource" )
public DataSource dataSource()
{
    return DataSourceBuilder.create().build();
}

@Primary
@Bean( name = "entityManagerFactory" )
public LocalContainerEntityManagerFactoryBean entityManagerFactory( EntityManagerFactoryBuilder builder,
        @Qualifier( "dataSource" ) DataSource dataSource )
{
    return builder.dataSource(dataSource).packages("com.virat.webservices.datastore.v1.Model")
            .persistenceUnit("db1").build();
}

@Primary
@Bean( name = "transactionManager" )
public PlatformTransactionManager transactionManager(
        @Qualifier( "entityManagerFactory" ) EntityManagerFactory entityManagerFactory )
{
    return new JpaTransactionManager(entityManagerFactory);
}
}

and

@Configuration
@EnableTransactionManagement
@EnableJpaRepositories( entityManagerFactoryRef = "v2EntityManagerFactory", transactionManagerRef = "v2TransactionManager",    basePackages = {
    "com.virat.datastore.repository" } )
@EntityScan( "com.virat.datastore.model" )
public class V2DBConfig {

@Bean( name = "v2DataSource" )
@ConfigurationProperties( prefix = "spring.datasource" )
public DataSource dataSource()
{
    return DataSourceBuilder.create().build();
}

@Bean( name = "v2EntityManagerFactory" )
public LocalContainerEntityManagerFactoryBean barEntityManagerFactory( EntityManagerFactoryBuilder builder,
        @Qualifier( "v2DataSource" ) DataSource dataSource )
{
    return builder.dataSource(dataSource).packages("com.virat.model")
            .persistenceUnit("db2").build();
}

@Bean( name = "v2TransactionManager" )
public PlatformTransactionManager barTransactionManager(
        @Qualifier( "v2EntityManagerFactory" ) EntityManagerFactory barEntityManagerFactory )
{
    return new JpaTransactionManager(barEntityManagerFactory);
}
}

And I configured my application.properties file as, 我将application.properties文件配置为,

spring.datasource.type=com.zaxxer.hikari.HikariDataSource
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.datasource.url=jdbc:mysql://localhost:3306/db2?      useUnicode=true&useJDBCCompliantTimezoneShift=true&useLegacyDatetimeCode=fal.   se&serverTimezone=UTC&useSSL=false
spring.datasource.username=root
spring.datasource.password=
#spring.datasource.pool.size=20
v1.datasource.driver-class-name=com.mysql.jdbc.Driver
v1.datasource.url=jdbc:mysql://localhost:3306/db1?     useUnicode=true&useJDBCCompliantTimezoneShift=true&useLegacyDatetimeCode=fal.   se&serverTimezone=UTC&useSSL=false
v1.datasource.username=root
v1.datasource.password=
#v1.datasource.pool.size=20
spring.jpa.properties.hibernate.id.new_generator_mappings=false
v1.jpa.properties.hibernate.id.new_generator_mappings=false
#spring.jpa.hibernate.ddl-auto=update
spring.jpa.show-sql=true

But when I run the application, the following exception has been thrown. 但是当我运行应用程序时,抛出了以下异常。

***************************
APPLICATION FAILED TO START
***************************

Description:

Field entityManager in com.highpeak.tlp.webservices.services.impl.TaskServiceImpl required a single bean, but 2 were found:
    - org.springframework.orm.jpa.SharedEntityManagerCreator#0: defined by method 'createSharedEntityManager' in null
    - org.springframework.orm.jpa.SharedEntityManagerCreator#1: defined by method 'createSharedEntityManager' in null


Action:

Consider marking one of the beans as @Primary, updating the consumer to accept multiple beans, or using @Qualifier to identify the bean that should be consumed

 org.springframework.boot.diagnostics.LoggingFailureAnalysisReporter org.springframework.boot.diagnostics.LoggingFailureAnalysisReporter:42 - 

***************************
APPLICATION FAILED TO START
***************************

Description:

Field entityManager in com.highpeak.tlp.webservices.services.impl.TaskServiceImpl required a single bean, but 2 were found:
    - org.springframework.orm.jpa.SharedEntityManagerCreator#0: defined by method 'createSharedEntityManager' in null
    - org.springframework.orm.jpa.SharedEntityManagerCreator#1: defined by method 'createSharedEntityManager' in null


Action:

Consider marking one of the beans as @Primary, updating the consumer to accept multiple beans, or using @Qualifier to identify the bean that should be consumed

Disconnected from the target VM, address: '127.0.0.1:56875', transport: 'socket'

Process finished with exit code 1

I am unable to identify what is the error. 我无法确定错误是什么。 I have two modules. 我有两个模块。 The repository and entity class of one database is in one module and the other database's classes in another module. 一个数据库的repositoryentity类位于一个模块中,另一个数据库的类位于另一个模块中。 Is this causing issue? 这会导致问题吗?

EDIT 编辑

My TaskServiceImpl.java 我的TaskServiceImpl.java

package com.virat.webservices.services.impl;


@Service
public class TaskServiceImpl implements TaskService {

    private static final Logger LOGGER = LoggerFactory.getLogger(TaskServiceImpl.class);

    @Autowired
    @PersistenceContext(unitName = "v2EntityManagerFactory")
    private EntityManager entityManager;

    @Value( "${file.base.path}" )
    private String basePath;

    @Value( "${application.domain}" )
    private String applicationDomain;

    @Value( "${application.protocol}" )
    private String applicationProtocol;

    @Value( "${server.port}" )
    private String serverPort;

    @Override
    @SuppressWarnings( "unchecked" )
    @Transactional( rollbackOn = DataException.class )
    public Integer doSomething( SomeObject someObject,
            UserAccessDetails userAccessDetails ) throws DataException
    {
        try
        {
            // Do input validations
            if( NullEmptyUtils.isNull(userAccessDetails) || NullEmptyUtils.isNull(someObject) )
            {

                throw new DataException(GeneralConstants.EXCEPTION, GeneralConstants.NULL_INPUT_ERROR,
                        HttpStatus.BAD_REQUEST);
            }

            // Creates a native mysql query based on the contents of lawyerDiscoveryParamsBean
            /* Should be replaced with criteria API */
            String generatedQuery = DynamicQueryGenerator.getDynamicQuery(someObject, owner);
            LOGGER.info("Generated query: {}", generatedQuery);
            Query executableQuery = entityManager.createNativeQuery(generatedQuery, UserModel.class);

            List<UserModel> userModels = executableQuery.getResultList();

            if( userModels.isEmpty() )
            {

                return 0;
            }

            return 1;

        }
        catch( DataException e )
        {
            LOGGER.error(GeneralConstants.ERROR, e);
            throw e;
        }
        catch( Exception e )
        {
            LOGGER.error(GeneralConstants.ERROR, e);
            throw new DataException(GeneralConstants.EXCEPTION, GeneralConstants.SOMETHING_WENT_WRONG,
                    HttpStatus.INTERNAL_SERVER_ERROR);
        }
    }

}

In your TaskServiceImpl make sure you annotate the persistenceContext correctly. TaskServiceImpl确保正确注释persistenceContext。

For example: 例如:

@PersistenceContext(unitName = "entityManagerFactory")
private EntityManager em;

In V1DBConfig.java , the annotation @EnableJpaRepository should actually be like this, V1DBConfig.java ,注释@EnableJpaRepository应该是这样的,

@EnableJpaRepositories( entityManagerFactoryRef = "entityManagerFactory", transactionManagerRef = "transactionManager", basePackages = {
        "com.virat.webservices.datastore.v1.Repo" } )

You have done the configuration right in the class V2DBConfig.java (Look at the @EnableJpaRepository annotation). 您已在V2DBConfig.java类中完成了配置(请查看@EnableJpaRepository注释)。 Do the same thing in V1DBConfig.java . V1DBConfig.java执行相同的V1DBConfig.java

And then, in your TaskServiceImpl.java , provide PersistenceContext , as answered by @Dan . 然后,在您的TaskServiceImpl.java ,提供PersistenceContext ,由@Dan回答。 I hope this helps. 我希望这有帮助。

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