MySql：使用IN运算符的Select语句

Question

I have a table with several fields and one field having 3 Comma Separated Values

 Column 1 Column 2 
    1        1,2,3
    2        2,3,4
    3        6,7,8 

Now i want to run an SQL query which fetches me the rows which have the value i send as an input.

Like in the above example, if i send a value 2 as an input to the function, it must return the 1st 2 rows.

I tried using the IN operator but failed as it does not fetch the rows which have the input i send as the 2nd or 3rd value of the CSV. In this example, it does not return the 1st row.

Can someone please help me out with this?

Thanks in Advance, Akash

Answer 1

You can use FIND_IN_SET() :

SELECT column1 FROM table WHERE FIND_IN_SET('2', column2) != 0

The IN operator is basically a shortcut for lots of ORs:

WHERE column2 = IN ('a', 'b', 'c')

gives the same result as

WHERE (column2 = 'a' OR column2 = 'b' OR column2 = 'c')

Answer 2

If I have understood your question correctly then how about trying - select Column1, Column2 from Table where Column1 <=

cheers

Answer 3

您应该可以使用Like来执行此操作，例如：

SELECT * FROM tablename WHERE [Column 2] LIKE ("%2%");