fiori 启动板中的稳定 ID

Question

I am using a FlexColumnLayout for my app.

In the mid column I need to access a controll of the begin column of the FlexColumnLayout. Here is the problem:

Since it is a different view I cannot use

this.getView().byId("myId")

My first solution was to use stable ID's, by giving the views (XML) IDs. Like that I could use:

sap.ui.getCore().byId("application---viewId--myId")

At first it worked just fine, but now that I integrated my app into the fiori launchpad the first part of the stable ID (the part before "viewId") changed and when I transport into productive it will change again.

Is there a way to access the mid column controls without sap.ui.getCore().byId? Or is there a way to load the first part dynamically so I don't need to change my IDs when tranporting?

Sadly I don't know how to reproduce a Launchpad for testing purposes, but for those who want to test their ideas about my problem, my FlexColumnLayout is build just like in the DemoApp: https://sapui5.hana.ondemand.com/#/entity/sap.f.FlexibleColumnLayout

Answer 1

Ok guys i found a solution:

this.getView().getParent().getParent()

returns the FlexColumnLayout. This has a method called "getBeginColumnPages", which returns an array of the views representing the begin column. Now that i can access the view in which my control is found, i can access it with the sap.ui.core.mvc.View.byId() method.

Now I have

this.getView().getParent().getParent().getMidColumnPages()[0].byId("myId")

Since the doulbe .getParent() doesn't seem to be ideal, please post a better solution if you know one : D

Answer 2

您必须使用createId()函数，这将返回控件的完整 ID。

this.byId(this.createId("myid"));