Python + Selenium WebDriver：在新标签页中打开URL

Question

I have a text document with a single URL on every line. I want each URL to be opened in a new tab. Heres what I have so far:

tabs = 0
f = open('links.txt', 'r', encoding='utf-8')
for line in f:
    url = line
    driver.execute_script("window.open(url, 'new_window')")
    sleep(7) # time to let tge page load
    tabs = tabs + 1 # to keep track of how many tabs I have

This gives me the error:

Traceback (most recent call last): File "scraper.py", line 100, in driver.execute_script("window.open(url, 'new_window')") File "C:\\Python37\\lib\\site-packages\\selenium\\webdriver\\remote\\webdriver.py", line 635, in execute_script 'args': converted_args})['value'] File "C:\\Python37\\lib\\site-packages\\selenium\\webdriver\\remote\\webdriver.py", line 320, in execute self.error_handler.check_response(response) File "C:\\Python37\\lib\\site-packages\\selenium\\webdriver\\remote\\errorhandler.py", line 242, in check_response raise exception_class(message, screen, stacktrace) selenium.common.exceptions.WebDriverException: Message: unknown error: url is not defined

I have tried everything, but can't get it to work. Any Ideas?

Answer 1

You are trying to pass url variable incorrectly in execute_script . Do this instead -

    tabs = 0
    f = open('links.txt', 'r', encoding='utf-8')
    for line in f:
        url = line
        driver.execute_script("window.open(arguments[0])", url)
        sleep(7) # time to let tge page load
        tabs = tabs + 1 # to keep track of how many tabs I have

Where, arguments[0] refers to your url.