[英]Calling a fortran dll from python using cffi
I am currently working on a simultion-tool that requires a PDE Solver from a Fortran dll. 我目前正在使用simultion工具,该工具需要来自Fortran dll的PDE解算器。 In order to figure how calling a dll from python I used a simpler function from the same dll but can't get it to work.
为了弄清楚如何从python调用dll,我从同一个dll使用了一个更简单的函数,但无法使其正常工作。
Systemspecs: Windows 7 Professional (64bit) Spyder 3.2.8 Python 3.6.5 (32bit) 系统规格:Windows 7专业版(64位)Spyder 3.2.8 Python 3.6.5(32位)
I am now using cffi to call the fortran function but it doesn't work either. 我现在正在使用cffi调用fortran函数,但是它也不起作用。
import cffi as cf
ffi=cf.FFI()
lib=ffi.dlopen("C:\Windows\SysWOW64\DLL20DDS")
ffi.cdef("""
double S01BAF(double X, int IFAIL);
""")
print (lib) #This works
print (lib.S01BAF) #This works
x = 1.
ifail = 0
print (lib.S01BAF(x,ifail)) #This doesn't work
This is the code i am using to call the function with cffi. 这是我使用cffi调用函数的代码。 The dll i am loading contains the function S01BAF which i intend to call.
我正在加载的dll包含我要调用的函数S01BAF。 The error message I recieve is:
我收到的错误消息是:
runfile('C:/Users/Student/Desktop/Minimal.py', wdir='C:/Users/Student/Desktop')
<cffi.api._make_ffi_library.<locals>.FFILibrary object at 0x0759DB30>
<cdata 'double(*)(double, int)' 0x105BBE30>
Kernel died, restarting
I don't know what that means. 我不知道那是什么意思
To check if the function itself is working I tryed calling it from a different language (VBA) and it worked just fine. 为了检查该函数本身是否正常工作,我尝试使用另一种语言(VBA)对其进行调用,并且工作正常。
Option Base 1
Option Explicit
Private Declare Function S01BAF Lib "DLL20DDS.dll" (x As Double, iFail As Long) As Double
Sub ln()
Dim iFail As Long
Dim x As Double
Dim y As Double
x = 1
iFail = 0
y = S01BAF(x, iFail)
MsgBox y
End Sub
The messagebox displays the correct value for ln(2). 该消息框显示ln(2)的正确值。
I have read the previously asked questions but couldn't apply the answers to my problem. 我已经阅读了之前提出的问题,但是无法将答案应用于我的问题。
Here is the code that works thanks to @Joe! 这是使用@Joe的代码!
ffi=cf.FFI()
lib=ffi.dlopen("C:\Windows\SysWOW64\DLL20DDS")
ffi.cdef("double S01BAF(double *x, int *ifail);")
x_1 = np.arange(-0.99,1,0.001)
x = ffi.new('double*', 1)
ifail = ffi.new('int*', 0)
y = (lib.S01BAF(x,ifail))
Cheers, Thilo 干杯,蒂洛
The function definition of S01BAF S01BAF的功能定义
double s01baf_ (const double *x, Integer *ifail)
indicates that the variables x
and ifail
are pointers. 指示变量
x
和ifail
是指针。 Please try 请试试
x = cf.new('double*', 1.0)
ifail = cf.new("int*", 0)
lib.S01BAF(x, ifail)
or 要么
x = cf.new('double*')
x[0] = 1.0
ifail = cf.new("int*")
ifail[0] = 0
lib.S01BAF(x, ifail)
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