根据数字中的第二个数字更改显示值

Question

I have a vue filter and display some values. I would like to change the value when the value's last digit is between 2 and 4. I need to have an automatised code so it works for all possible intervals, for example: (22-24, 32-34, 622-624...) . I managed to find the last digit of a value: value.toString()[value.toString().length - 1] . I am not sure how to solve this problem, maybe I should come up with a special matematical formula?

myfilter: (value): => {
    if(value >= 22 && value <= 24) {
        return 'my new value'
    }
}

Answer 1

You can use the modulus operator: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators#Remainder_()

myfilter: (value): => {
    if(value % 10 <= 4 && value % 10 >= 2 ) {
        return 'my new value'
    }
}