如何判断代码是否在try catch块下

Question

Is there a way to know if the some code is under a try catch block? (specifically in node)

What I want to do is something like this (using a variable bungleInTry to simulate what I am looking for)

 let acumulateErrors=[]; let bungleInTry=0; // This to be removed, it's to simulate the expected behavior function assert(cond,msg){ if (!cond){ if (underTryCatch()) throw(Error(msg)); // Somewhere somebody is in control else acumulateErrors.push(msg); // I don't want a crash but I have to keep this } } assert(1==2, "1 doesn't equals 2"); bungleInTry++; // (simulating what I am asking) try{ assert(3==4, "3 doesn't equals 4"); }catch(error){ console.log(error.message); } bungleInTry--; // to be removed console.log(acumulateErrors); function underTryCatch(){ return bungleInTry; } 

Answer 1

No, there's no way of detecting that an error thrown will be caught, that information just isn't available to your code. (And arguably, all errors are caught, even if they're caught by Node's own error handler that dumps them out to the console and terminates the process... :-) )