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使用jQuery中的一个按钮隐藏/显示div

[英]Hide / show div using one button in jQuery

I am trying to hide one element and show the other when when button is clicked and switch around when it is clicked again. 我试图隐藏一个元素,当单击按钮时显示另一个元素,并在再次单击时切换。

I came up with something like this but this isn't going to work... 我想出了类似的东西,但是这行不通...

 jQuery("#wcvat-toggle").click(function() { jQuery("#excltaxout").show(); jQuery("#incltaxout").hide(); }); 
 <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <a id="wcvat-toggle"> <span id="incltaxout">Including Tax</span> <span id="excltaxout">Excluding Tax</span> </a> 

However this will always show the #excltaxout . 但是,这将始终显示#excltaxout Any suggestions? 有什么建议么?

To make this work - and assuming that one of those elements starts hidden - you can simply call toggle() on them both at the same time. 为了使这项工作有效-并假设其中一个元素开始隐藏-您可以简单地同时在两个元素上调用toggle() This will invert their display states. 这将反转其display状态。

 jQuery(function($) { $("#wcvat-toggle").click(function() { $("#excltaxout, #incltaxout").toggle(); }); }); 
 #excltaxout { display: none; } 
 <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <a id="wcvat-toggle"> <span id="incltaxout">Including Tax</span> <span id="excltaxout">Excluding Tax</span> </a> 

You can use jQuery's .toggle() : 您可以使用jQuery的.toggle()

Display or hide the matched elements. 显示或隐藏匹配的元素。

 $("#wcvat-toggle").click(() => { $("#incltaxout").toggle(); $("#excltaxout").toggle(); }); 
 #incltaxout {display:none} 
 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <a id="wcvat-toggle"> <span id="incltaxout">Including Tax</span> <span id="excltaxout">Excluding Tax</span> </a> 

Note however that this only works if one element is hidden by default, if not you will hide/show both at once. 但是请注意,这仅在默认情况下隐藏一个元素时才有效,否则,您将一次隐藏/显示两个元素。

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