有没有一种简单的方法可以从c ++中的路径获取文件名？

Question

Currently I am getting a file's path with GetModuleFileName and storing it in szExeFilePath by doing:

TCHAR szExeFilePath[MAX_PATH];
GetModuleFileName(NULL, szExeFilePath, MAX_PATH);

And that returns C:\\\\dev\\\\program\\\\Debug\\\\program.exe

However I also want to store just the program.exe . I looked around and saw _splitpath_s might be the easiest way of doing this. The only problem is that I didn't see any explanation on how to actually use _splitpath_s and I can't get it to work at all.

So basically I am asking how to use _splitpath_s or if there is a simpler/easier method of getting the filename of the executable.

Answer 1

However I also want to store just the program.exe

With C++17 you could simple use std::filesystem

#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;

int main()
{
    std::cout << fs::path("C:/dev/program/Debug/program.exe").filename() << '\n' ;
}

Demo here