按长度和最后 N 个字符对字符串列表进行排序

Question

I'm trying to solve a problem, where I have to sort a list of strings by the length of the string as well as the last characters in the string. In the case of the string having the same length and same last character, they should be sorted by second to last character and so on.

I have this code, but I'm not clear on why it does not work as I intend. Could someone point me in the right direction?

My code:

import sys

word_lists = [line.split(' ') for line in ' '.join([x.strip() for x in sys.stdin.readlines()]).split('  ')]
for i in range(0, len(word_lists)):
    word_lists[i] = sorted((word_lists[i]), key=lambda x: (x[:-1], len(x)))

Input:

apple
banana
grape
kiwi
pear

airplane
bicycle
boat
car

Output:

[['apple', 'banana', 'grape', 'kiwi', 'pear'], ['airplane', 'bicycle', 'boat', 'car']]

Expected Output:

[['banana', 'apple', 'grape', 'kiwi', 'pear'], ['bicycle', 'airplane', 'car', 'boat']]

Answer 1

Use x[::-1] .

Ex:

l = [['apple', 'banana', 'grape', 'kiwi', 'pear'], ['airplane', 'bicycle', 'boat', 'car']]
for i in l:
    print(sorted(i, key=lambda x: (x[::-1], len(x))))

Output:

['banana', 'apple', 'grape', 'kiwi', 'pear']
['bicycle', 'airplane', 'car', 'boat']

---

output = [sorted(i, key=lambda x: (x[::-1], len(x))) for i in l]
print(output)
--> [['banana', 'apple', 'grape', 'kiwi', 'pear'], ['bicycle', 'airplane', 'car', 'boat']]

Answer 2

如果您想首先按字符串长度对数据进行排序，那么您必须更改代码中的键顺序，并且您希望您的字符串按字母顺序从尾部排序，因此您必须从尾部 (x[::-1]) 发送字符，所以最后您必须通过 key(len(x), x[::-1]) 更改您的密钥