[英]How to use Laravel Blade in JS (PHP)
I am developing a blog project in Laravel 5.6. 我正在Laravel 5.6中开发一个博客项目。 I am using the Laravel built-in function called
str_slug()
to convert titles into slugs and JavaScript to auto generate the slugs using JavaScript's keyup
function. 我正在使用Laravel内置函数
str_slug()
将标题转换为str_slug()
并使用JavaScript使用JavaScript的keyup
函数自动生成str_slug()
。 Here's my code: 这是我的代码:
var postTitle = $('#post-title');
var postSlug = $('#post-slug');
postTitle.keyup(function() {
postSlug.val({{ str_slug(postTitle.val()) }});
});
However, it's throwing an error of unknown constant. 但是,它将引发未知常量的错误。 Can anyone tell me how to what I want?
谁能告诉我我想要什么? I am new to Laravel.
我是Laravel的新手。
Here's a simple function to create a slug in JS: 这是一个在JS中创建子弹的简单函数:
function slugify(text)
{
return text.toString().toLowerCase()
.replace(/\s+/g, '-') // Replace spaces with -
.replace(/[^\w\-]+/g, '') // Remove all non-word chars
.replace(/\-\-+/g, '-') // Replace multiple - with single -
.replace(/^-+/, '') // Trim - from start of text
.replace(/-+$/, ''); // Trim - from end of text
}
You can use the html markup to get this done. 您可以使用html标记来完成此操作。 In the html mark up create a hidden input and put in the value of
str_str()
operation on the post-title and in your js set the post-slug input value to that on keyup. 在html标记中,创建一个隐藏的输入,并将
str_str()
上的str_str()
操作的值str_str()
,在您的js中,将str_str()
后的输入值设置为keyup上的值。
<input type="text" id="post-title" value="{{$title}}">
<input type="hidden" id="hidden-post-title" value="{{str_slug($title)}}">
var postTitle = $('#post-title');
var postSlug = $('#post-slug');
postTitle.keyup(function() {
postSlug.val($('#hidden-post-title').val());
});
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