[英]Django Rest Framework custom message for 404 errors
I have a generic class based view: 我有一个基于通用类的视图:
class ProjectDetails(mixins.RetrieveModelMixin,
mixins.UpdateModelMixin,
generics.GenericAPIView):
queryset = Project.objects.all()
# Rest of definition
And in my urls.py
, I have: 在我的
urls.py
,我有:
urlpatterns = [
url(r'^(?P<pk>[0-9]+)/$', views.ProjectDetails.as_view())
]
When the API is called with a non-existent id, it returns HTTP 404
response with the content: 当使用不存在的id调用API时,它将返回带有内容的
HTTP 404
响应:
{
"detail": "Not found."
}
Is it possible to modify this response? 是否可以修改此响应?
I need to customize error message for this view only . 我只需要为此视图自定义错误消息。
This solution affect all views: 此解决方案影响所有视图:
Surely you can supply your custom exception handler: Custom exception handling 当然,您可以提供自定义异常处理程序: 自定义异常处理
from rest_framework.views import exception_handler
from rest_framework import status
def custom_exception_handler(exc, context):
# Call REST framework's default exception handler first,
# to get the standard error response.
response = exception_handler(exc, context)
# Now add the HTTP status code to the response.
if response.status_code == status.HTTP_404_NOT_FOUND:
response.data['custom_field'] = 'some_custom_value'
return response
Sure you can skip default rest_framework.views.exception_handler
and make it completely raw. 当然你可以跳过默认的
rest_framework.views.exception_handler
并使它完全原始。
Note: remember to mention your handler in django.conf.settings.REST_FRAMEWORK['EXCEPTION_HANDLER']
注意:记得在
django.conf.settings.REST_FRAMEWORK['EXCEPTION_HANDLER']
提及你的处理程序
Solution for specific view: 特定视图的解决方案:
from rest_framework.response import Response
# rest of the imports
class ProjectDetails(mixins.RetrieveModelMixin,
mixins.UpdateModelMixin,
generics.GenericAPIView):
queryset = Project.objects.all()
def handle_exception(self, exc):
if isinstance(exc, Http404):
return Response({'data': 'your custom response'},
status=status.HTTP_404_NOT_FOUND)
return super(ProjectDetails, self).handle_exception(exc)
It's possible by overriding specific methods like update
, retrieve
as: 可以通过覆盖
update
等特定方法, retrieve
为:
from django.http import Http404
from rest_framework.response import Response
class ProjectDetails(mixins.RetrieveModelMixin,
mixins.UpdateModelMixin,
generics.GenericAPIView):
queryset = Project.objects.all()
def retrieve(self, request, *args, **kwargs):
try:
return super().retrieve(request, *args, **kwargs)
except Http404:
return Response(data={"cusom": "message"})
def update(self, request, *args, **kwargs):
try:
return super().update(request, *args, **kwargs)
except Http404:
return Response(data={"cusom": "message"})
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