[英]How to define a const array in typescript
My Code:我的代码:
const WEEKDAYS_SHORT: string[] = ['Dim', 'Lun', 'Mar', 'Mer', 'Jeu', 'Ven', 'Sam']
the error message comes from TypeScript (3.0) compiler:错误消息来自 TypeScript (3.0) 编译器:
TS2322: Type 'string[]' is not assignable to type '[string, string, string, string, string, string, string]'.
TS2322:类型 'string[]' 不能分配给类型 '[string, string, string, string, string, string, string]'。 Property '0' is missing in type 'string[]'.
类型“string[]”中缺少属性“0”。
if I change the string[]
to ReadonlyArray<string>
, then the error message becomes:如果我将
string[]
更改为ReadonlyArray<string>
,则错误消息变为:
TS2322: Type 'ReadonlyArray' is not assignable to type '[string, string, string, string, string, string, string]'.
TS2322:类型“ReadonlyArray”不可分配给类型“[字符串、字符串、字符串、字符串、字符串、字符串、字符串]”。 Property '0' is missing in type 'ReadonlyArray'.
“ReadonlyArray”类型中缺少属性“0”。
my tsconfig.json:我的 tsconfig.json:
{
"compilerOptions": {
"declaration": false,
"emitDecoratorMetadata": true,
"experimentalDecorators": true,
"lib": ["es6", "dom"],
"module": "es6",
"moduleResolution": "node",
"sourceMap": true,
"target": "es5",
"jsx": "react",
"strict": true
},
"exclude": [
"**/*.spec.ts",
"node_modules",
"vendor",
"public"
],
"compileOnSave": false
}
how can I define a readonly array in TypeScript?如何在 TypeScript 中定义只读数组?
You may add as const
to your declaration; 您可以在声明中添加
as const
;
const readonlyArray = [1, 2, 3] as const;
Furthermore the type typeof readonlyArray[number]
would be 1 | 2 | 3
此外,
typeof readonlyArray[number]
的类型将为1 | 2 | 3
1 | 2 | 3
After debugging, I found it is not TypeScript compiler problem, it is because I used a third-party component call DayPicker: 调试后,我发现这不是TypeScript编译器问题,这是因为我使用了第三方组件调用DayPicker:
<DayPicker
onDayClick={this.handleDayClick}
selectedDays={posts.day}
months={MONTHS}
weekdaysShort={WEEKDAYS_SHORT}
firstDayOfWeek={1}/>
the type of the prop weekdaysShort
is not string[]
, but [string, string, string, string, string, string, string]
道具
weekdaysShort
的类型不是string[]
,而是[string, string, string, string, string, string, string]
weekdaysShort?: [string, string, string, string, string, string, string];
so TS compile says string[]
doesn't match [string, string, string, string, string, string, string]
. 因此TS编译会说
string[]
与[string, string, string, string, string, string, string]
不匹配。
finally, I just changed the type from string[]
to any
to avoid this anoy error message, of course, we can change to [string, string, string, string, string, string, string]
as well (too long). 最后,我只是将类型从
string[]
更改为any
以避免出现此错误消息,当然,我们也可以更改为[string, string, string, string, string, string, string]
(太长)。
As you point out the issue is cause because you try to assign the string array ( string[]
) to a 7-string-tuple. 如您所指出的,问题是由原因造成的,因为您尝试将字符串数组(
string[]
)分配给7字符串元组。 While your solution to use any
will work it's not generally advisable to use any
. 虽然您可以使用
any
解决方案,但通常不建议使用any
。 Spelling out the supple is also not ideal since it's soo long. 由于太长了,拼写出柔顺也不理想。
What we can do is create a helper function to create a tuple type. 我们可以做的是创建一个辅助函数来创建一个元组类型。 This function is reusable for anywhere you need tuple:
此功能可在需要元组的任何地方重用:
function tupleArray<T extends any[]>(...v: T) {
return v;
}
const WEEKDAYS_SHORT_INFFERED = tupleArray('Dim', 'Lun', 'Mar', 'Mer', 'Jeu', 'Ven', 'Sam') // INFFERED AS [string, string, string, string, string, string, string]
const WEEKDAYS_SHORT: [string, string, string, string, string, string, string] = WEEKDAYS_SHORT_INFFERED
I did not reproduce the issue on the TypeScript playground . 我没有在TypeScript操场上重现该问题。
But, what about using the inferred type, regardless of what it is (string array string[]
or 7-string tuple [string, string, string, string, string, string, string]
)? 但是,无论使用什么类型(字符串数组
string[]
或7字符串元组[string, string, string, string, string, string, string]
),如何使用推断的类型呢?
const WEEKDAYS_SHORT = ['Dim', 'Lun', 'Mar', 'Mer', 'Jeu', 'Ven', 'Sam'];
const sunday = 0;
const dayShortName = WEEKDAYS_SHORT[sunday]; // => 'Dim'
Or an enum? 还是一个枚举?
enum WEEKDAYS_SHORT { 'Dim', 'Lun', 'Mar', 'Mer', 'Jeu', 'Ven', 'Sam' }
const sunday = 0;
const dayShortName = WEEKDAYS_SHORT[sunday]; // => 'Dim'
IMO, both option above are better than specifying the type any
in this case. 国际海事组织,这两个选项上比指定类型更好
any
在这种情况下。
While the accepted answer is correct, it does have a drawback.虽然接受的答案是正确的,但它确实有一个缺点。
const readonlyArray = [1, 2, 3] as const;
let x = 4; // function parameter, etc.
// Argument of type 'number' is not assignable to parameter of type '1 | 2 | 3'.ts(2345)
// if (readonlyArray.includes(x)) {}
One alternative is to use readonly
:一种替代方法是使用
readonly
:
const readonlyArray: readonly number[] = [1, 2, 3];
let x = 4;
if (readonlyArray.includes(x)) {} // OK
// Property 'push' does not exist on type 'readonly number[]'.ts(2339)
// readonlyArray.push(4);
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