仅当具有相同ID的所有项目在另一列中都具有相同的值时，才返回行

Question

I am trying to figure out a way to identify all ID's that only contain all of the same value in another column.

In the example above Looking for all SubID's that are inactive it would only return rows for C2 (ID's 2, 5, & 6).

Sample Data :

Answer 1

use group by and sub-query

  select t.* from 
  (select subid,status from t t1     
   group by subid,status
   having count(*)>1
  ) as t1       
  inner join t on t.subid=t1.subid and t.status=t1.status

Answer 2

You use not exists :

select t.*
from table t
where not exists (select 1 from table t1 where t1.subid = t.subid and t1.status = 'Active');

EDIT : If you want to get the subid s which have same status then you can do :

select t.*
from table t
where not exists (select 1 from table t1 where t1.subid = t.subid and t1.status <> t.status);