使用grepl（）从R中的数据框中删除值

Question

I have a data.frame with 1 column, and a nondescript number of rows.

This column contains strings, and some strings contain a substring, let's say "abcd" .

I want to remove any strings from the database that contain that substring. For example, I may have five strings that are "123 abcd" , and I want those to be removed.

I am currently using grepl() to try and remove these values, but it is not working. I am trying:

data.frame[!grepl("abcd", dataframe)]

but it returns an empty data frame.

Answer 1

我们可以使用grepl来获取逻辑向量，取反（ ! ），然后使用它来对'数据'进行子集化

data[!grepl("abcd", data$Col),,drop = FALSE]