具有正确链接的 404 错误 Flask

Question

I'm working on flask app, but whenever I try to run run.py , I get a 404 . Here is my views page:

from flask import render_template, flash, 

redirect, Flask, request
from app import app
import sqlite3 as sql
import csv
import os


app = Flask(__name__)
app.url_map.strict_slashes = False
@app.route('/')
def home():
    print(10999)
    return render_template('base.html')


@app.route('/2018_draft')
def list():
   con = sql.connect("database.db")
   con.row_factory = sql.Row

   cur = con.cursor()
   cur.execute("SELECT * FROM BPM")

   rows = cur.fetchall();
   return render_template("table.html",rows = rows)

if __name__ == '__main__':
   app.run(debug = True)

Ignoring the sqlite code, why am I getting a 404 ? It doesn't work when I manually go to localhost:5000/base.html , or localhost:5000/ or localhost:5000/2018_draft either.

Answer 1

I believe that the issue is on the path of templates, probably Flask can't find them.

Assuming that your file's name is run.py the organization of folders should be:

/parent_folder
    /static
    /templates
    run.py

/static is the folder that you put js/css files that your html may import. /templates you put the html files that you want to render with render_template("table.html",rows = rows)

I'm not sure why you import the from app import app , it is not necessary unless you create the Flask(__name__) in other file.