如何在不循环的情况下打印项目名称？

Question

This is the code:

itemDict = {"Laptop" : 3499.0, "Keyboard" : 10.5, "Harddisk" : 159.3, "Mouse" : 8.9}

print("Item Listing")

print("---------------------")

def displayItem(itemDict):
    i = list(itemDict.values())

    return i
def names(itemDict):
    j = list(itemDict.keys())

    return j
for names in names(itemDict):
    for values in displayItem(itemDict):
        print(names + " - $" + str(values))

Answer 1

Or a one-liner:

d = {"Laptop" : 3499.0, "Keyboard" : 10.5, "Harddisk" : 159.3, "Mouse" : 8.9}
print('\n'.join(' - $'.join(map(str,i)) for i in zip(sorted(list(d.keys())*len(d),key=list(d.keys()).index),sorted(list(d.values())*len(d),key=list(d.values()).index))))

Answer 2

You can make it a bit simpler if that is what you are looking for:

for i in itemsDict:
    print i, itemsDict[i]

that will print the key:value pair

For a dynamically changing Dict I don't think there is another way to print all the values other than iterating through it.

Hope that helps :)