C++ 17 | 调试输出

Question

What I want to do, is when I run a program in debug mode, I want it to cout to the console or even possibly the game window what it's doing, like for an example, GameWindow::Initialized(args...) , and I want that to run throughout the program until it ends. Also, if I get the functions for that (I believe there is some on google), instead of checking if it's in debug mode: 'if (_Debug) {}', for each time I want to call the function that cout's to the screen, is there a way I can just do the debug checking once and have it done?

My guess is that I could create a thread and have it check if it's in debug mode, I could use a function that checks live what the game is doing and have that run continuously. I need to do more on threading because I've not done it in a while.

Thanks for reading, if you could help me or even agree that my method would work, I'd highly appreciate that :)

Answer 1

Normally you #define NDEBUG if you are not in debug mode. So you can

#ifndef NDEBUG
    cout << "test\n";
#endif

Answer 2

Alright, so I've just decided to do something really simple, so all I done is define a log function which takes in a parameter and then output that to the console, if debug mode is on, otherwise, all I done is do an #else and then do the same thing, but I didn't output it. So just #define LOG(x) /* Nothing Else */ ->This is for release