[英]How to encode (base64) and decode(base64) more than one variable which is passing via url in php
I want to pass more than one variable via url. 我想通过网址传递多个变量。 I do not want to show those values to the user.Therefore while passing the variable via url I encode the by base64 and in another file I decode it and I will use.
我不想向用户显示这些值,因此在通过url传递变量时,我通过base64编码了编码,并在另一个文件中对其进行了解码并将使用。 I am able to do this for one variable.But, I want to implement the same for more than one variable.
我可以为一个变量执行此操作,但是我想为多个变量实现相同的操作。 I am not getting how to do this.
我没有怎么做。
Can anyone assist me? 谁能帮助我?
My code is, 我的代码是
encode.php encode.php
<?php
$link = "decrypt.php?item=".urlencode(base64_encode('testing'))."";
echo '<a href='.$link.'>click here</a>';
?>
decode.php decode.php
<?php
foreach($_GET as $loc=>$item)
$_GET[$loc] = base64_decode(urldecode($item));
echo $_GET[$loc];
?>
But, I should pass more than one like 但是,我应该通过多个
<a href="test.php?name="Suma"&place="India"">click</a>
How do I do this? 我该怎么做呢?
I got answer:) 我得到了答案:)
I have like this, 我有这样
My code is, 我的代码是
encode.php encode.php
<?php
$link = "decrypt.php?
item=".urlencode(base64_encode('testing'))."&rate=".urlencode(base64_encode('10'))."";
echo '<a href='.$link.'>click here</a>';
?>
decode.php decode.php
<?php
echo base64_decode(urldecode($_GET['item']));
echo base64_decode(urldecode($_GET['rate']));
?>
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