如何获得一个孩子以上的孩子？
[英]How to get element who has more than one child?
问题描述
In this code I get the number of children of all li elements. 
在这段代码中，我得到了所有li元素的子代数。 But how can I get li element who has more than one child? 但是我怎样才能得到一个孩子以上的李元素呢？
let liLength = document.querySelectorAll('li').length; for (let i = 0; i < liLength; i++) { let liChildrenLength = document.querySelectorAll('li')[i].children.length; console.log(liChildrenLength); }
<body> <ul> <li><a>list</a></li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> </ul> <script src="main.js"></script> </body>
4 个解决方案
解决方案1
2 2018-08-20 15:11:03
Convert the NodeList to an Array and use filter and childNodes . 将NodeList转换为Array并使用filter和childNodes 。
Depending on if you want the number of actual elements vs nodes to be greater than 1, you should swap childNodes for children . 根据您是否希望实际元素与节点的数量大于1，应将childNodes换为children 。 childNodes will include any node, while children only contains Elements . childNodes将包含任何节点，而children节点仅包含Elements 。 See this question for a little bit more detail: What is the difference between children and childNodes in JavaScript? 有关更多细节，请参见此问题：JavaScript中的child和childNodes有什么区别？
const arr = Array.from(document.querySelectorAll('li')).filter(li => li.childNodes.length > 1); console.log(arr);
<body> <ul> <li><a>list</a></li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> </ul> </body>
解决方案2
1 已采纳 2018-08-20 15:12:59
1- Store all li s in array instead of length 1-将所有li而不是长度存储在数组中
2- Iterate through them and check the number of children 2-遍历他们并检查孩子的数量
Something like this 像这样
let lis = document.querySelectorAll('li'); for (let i = 0; i < lis.length; i++) { if (lis[i].children.length > 1) { console.log(lis[i].children) console.log('------------------') } }
<body> <ul> <li><a>list</a></li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> </ul> <script src="main.js"></script> </body>
解决方案3
0 2018-08-20 15:09:50
var liLength = document.querySelectorAll('li').length; for (var i = 0; i < liLength; i++) { var liChildren = document.querySelectorAll('li')[i].children; if (liChildren.length > 1) for (var j = 0; j < liChildren.length; j++) console.log(liChildren[j]); }
<body> <ul> <li><a>list</a></li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> <li><a>list</a> <ul> <li><a>list</a></li> <li><a>list</a></li> </ul> </li> </ul> <script src="main.js"></script> </body>
Same as parsing through an array use [indexNumber] 与通过数组进行解析相同，使用[indexNumber]
liChildren = document.querySelectorAll('li')[i].children;
liChildren[someIndex]
Hope that was the question 希望这是问题
解决方案4
0 2018-08-20 15:11:11
try this: 尝试这个：
let li = [...document.querySelectorAll('li')].filter(function(li) {
return li.children.length;
});
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