Google 工作表脚本将数据集从一张工作表复制到另一张工作表的顶部（仅限值）

Question

I have a task that requires that I move data from one sheet to another (much like a log). I prefer that the each time more data is added it be to the top of the log sheet. Lets say sheet "index generation" has data in the first 3 rows. The three rows from "index generation" needs to be added to the top of sheet "index" without over-righting or having more than just 3 rows added.

Thanks for any help you might be able to offer!

Here is the current status but it has cannot find function getActiveSpreadSheet in object SpreadsheetApp.

function IndexCopy() {
  var app = SpreadsheetApp;
  var ss = app.getActiveSpreadSheet();
  var indexGen = ss.getSheetByName('Index Generation')
  var index = ss.getSheetByName('Index');
  var Rows = indexGen.range.getValues();
  var array = sheet.range.getValues();
array.splice(0, 0, Rows);
  // add three rows to sheet.range then 
index.range.setValues(array)
};

Answer 1

try something like this:

function onOpen() {
  var ui = SpreadsheetApp.getUi();
  // Or DocumentApp or FormApp.
  ui.createMenu('Custom Menu')
      .addItem('First item', 'indexCopy')
      .addToUi();
}

function indexCopy()
{
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var src = ss.getSheetByName('source');
  var dest = ss.getSheetByName('destination');
  var srcDatas = src.getDataRange().getValues();
  var destDatas = dest.getDataRange().getValues();
  var i = srcDatas.length - 1
  while (i >= 0)
    destDatas.splice(1, 0, srcDatas[i--]);
  dest.getRange("A1:B" + destDatas.length).setValues(destDatas);
}

look at this documentation

Answer 2

Give this a try: You first have to select the number of rows you want to move from the Index Generation Sheet and then run this function.

function IndexCopy() {
  var ss=SpreadsheetApp.getActive();
  var igSht=ss.getSheetByName('Index Generation');
  var igRg=igSht.getActiveRange();
  var igA=igRg.getValues();
  var iSht=ss.getSheetByName('Index');
  for(var i=0;i<igA.length;i++){
    iSht.insertRowBefore(1);
    iSht.getRange(1,1,1,igA[i].length).setValues([igA[i]]);
  }
  igSht.deleteRows(1, igA.length);
}