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从当前工作目录而不是从根目录获取路径

[英]Getting path from current working directory not from root

Hello everyone I am trying to get the path from the current working directory but I don't want the root path included with it in PHP or wordpress. 大家好,我正在尝试从当前工作目录获取路径,但是我不希望PHP或wordpress中包含根路径。 For example I have a directory structure like this. 例如,我有一个像这样的目录结构。

-C
--wamp64
--------www
-----------project
------------------Other directories

Now, what exactly I want is to get the path from project directory something like this. 现在,我真正想要的是从项目目录获取类似这样的路径。

-project
--Other directories

Currently with __DIR__ or dirname(__FILE__) I am getting. 目前正在使用__DIR__dirname(__FILE__)

C:\\wamp64\\www\\project\\other_directories C:\\ wamp64 \\ www \\ project \\ other_directories

But I want to get. 但是我想得到。

\\project\\other_directories \\ project \\ other_directories

And I wanted to make it dynamic so that it picks up the right path from which ever server I deploy this project. 而且我想使其动态化,以便它从我部署此项目的任何服务器上选择正确的路径。

I searhed alot but couldn't find the solution. 我晒了很多,但找不到解决方案。

https://www.w3schools.com/php/showphp.asp?filename=demo_global_server https://www.w3schools.com/php/showphp.asp?filename=demo_global_server

Check above URL and use $_SERVER['PHP_SELF']; 检查上面的URL,并使用$_SERVER['PHP_SELF'];

remove the filename from that and you will have the path relative to the document root. 从中删除文件名,您将拥有相对于文档根目录的路径。

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