Wiremock：不使用UI的HTTP网站测试

Question

我对如何在不使用UI的情况下测试HTTP网站提出了要求。可以说，我们有一个google网站搜索功能（不是Web服务），我需要对其进行测试。如何开始？任何人都可以举一些例子（JUnit）（ Get / Post方法）来启动该项目。我尝试阅读官方文档，但未找到任何相关信息。

Answer 1

You can do it with the following snippet

public class Searcher {

    public String search(String searchUrl, String searchWord) throws IOException, URISyntaxException {
        try (CloseableHttpClient httpClient = HttpClients.createDefault()) {
            URIBuilder builder = new URIBuilder(searchUrl);
            builder.setParameter("search_term", searchWord);

            HttpGet request = new HttpGet(builder.build());
            HttpResponse httpResponse = httpClient.execute(request);

            return convertResponseToString(httpResponse);
        }
    }

    private String convertResponseToString(HttpResponse response) throws IOException {
        try (Scanner scanner = new Scanner(response.getEntity().getContent(), "UTF-8")) {
            String responseString = scanner.useDelimiter("\\Z").next();

            return responseString;
        }
    }
}

public class SearcherTest {

    @Rule
    public WireMockRule wireMockRule = new WireMockRule(options().dynamicPort());

    @Test
    public void searchTest() throws IOException, URISyntaxException {
        String searchWord = "something";
        String expectedResult = "Your expected result";

        stubFor(get(urlPathEqualTo("/search"))
            .withQueryParam("search_term", equalTo(searchWord))
            .willReturn(aResponse()
                    .withBody(expectedResult)));

        Searcher searcher = new Searcher();
        String searchResult = searcher.search("http://localhost:" + wireMockRule.port() + "/search", searchWord);

        verify(getRequestedFor(urlPathEqualTo("/search"))
            .withQueryParam("search_term", equalTo(searchWord)));
        assertEquals(expectedResult, searchResult);
}

}