如何在python上用pywinauto打开一个excel文件？

Question

So Far, my code is:

from pywinauto import *
app = Application().start(r"C:\\Program Files (x86)\\Microsoft Office\\root\\Office16\\EXCEL.exe")
dlg = app.Excel
app = Application().connect(path=r"C:\\Program Files (x86)\\Microsoft Office\\root\\Office16\\EXCEL.exe")
dlg = app.Excel

But I can't Open a file!!

Any help would be apreciated!!

PS I am using the gui so I can use an excel extension

Answer 1

I open a file this way (don't forget to put "r" before both strings if you use single "\\")

from pywinauto import Application

program_path = r"C:\Program Files (x86)\Microsoft Office\root\Office16\EXCEL.exe"
file_path    = r"C:\file.xlsx"

app = Application().start(r'{} "{}"'.format(program_path, file_path))

Answer 2

If you just want to open an Excel program using Pywinauto, you can use this snippet codes as followed:

from pywinauto import Application

app = Application(backend="uia")
app.start(r"C:/Program Files/Microsoft Office/root/Office16/EXCEL.exe")