使用Jackson将包含模式和数据的Xml转换为Java对象

Question

I have tried Jackson API to parse below XML into java object but it did not work. I only want object that represents the student record . Can anybody help me with this? For standard xml format, the Jackson API works but for the below example I am not able to do so

  <?xml version="1.0" encoding="utf-8"?> <DataTable xmlns="http://*****.com"> <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:MainDataTable="StudentRecord" msdata:UseCurrentLocale="true"> <xs:complexType> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="StudentRecord"> <xs:complexType> <xs:sequence> <xs:element name="StudentId" type="xs:string" minOccurs="0" /> <xs:element name="FName" type="xs:string" minOccurs="0" /> <xs:element name="LName" type="xs:string" minOccurs="0" /> <xs:element name="Address1" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> </xs:element> </xs:choice> </xs:complexType> </xs:element> </xs:schema> <diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1"> <DocumentElement xmlns=""> <StudentRecord diffgr:id="StudentRecord1" msdata:rowOrder="0"> <StudentId>&&&&&&&</StudentId> <FName>ABC</FName> <LName>DSF</LName> <Address1>12345</Address1> </StudentRecord> </DocumentElement> </diffgr:diffgram> </DataTable> 

Answer 1

SimpleXml can do it, first 1 POJO:

public class StudentRecord {
    @XmlAttribute
    @XmlName("diffgr:id")
    public String id;
    @XmlAttribute
    @XmlName("msdata:rowOrder")
    public int rowOrder;
    @XmlName("StudentId")
    public String studentId;
    @XmlName("FName")
    public String firstName;
    @XmlName("LName")
    public String lastName;
    @XmlName("Address1")
    public String address1;
}

Next we turn the XML into a DOM, then we grab the element we need and convert that element to our class.

final SimpleXml simple = new SimpleXml();
final Element root = simple.fromXml(xml);
final StudentRecord student = simple.fromXml(root.children.get(1).children.get(0).children.get(0), StudentRecord.class);
System.out.println(student.id + " : " + student.firstName + " " + student.lastName);

This code will print:

StudentRecord1 : ABC DSF

SimpleXml is in maven central:

<dependency>
    <groupId>com.github.codemonstur</groupId>
    <artifactId>simplexml</artifactId>
    <version>1.5.5</version>
</dependency>