[英]UUID Mapping in hibernate
I have mapped a table to my table and trying to add some values in it.我已将一个表映射到我的表并尝试在其中添加一些值。 but I am getting errors as below
但我收到如下错误
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax;
引起:com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:你的SQL语法有错误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'create, delete, read, role_id, update, id) values (_binary'ØN_WlAs—\\niÊnÙ' at line 1
检查与您的 MySQL 服务器版本相对应的手册,以获取在“创建、删除、读取、role_id、更新、id”附近使用的正确语法(第 1 行的 _binary'ØN_WlAs—\\niÊnÙ')
my entities are我的实体是
RoleSettings.java角色设置.java
@Entity @Table(name = "role_settings")
@Getter @Setter @Data
public class RoleSettings implements Serializable {
private static final long serialVersionUID = 8862104773442047690L;
@Id
@GeneratedValue(generator = "uuid2")
@GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
private UUID id;
@ManyToOne
@JoinColumn(name = "role_id", referencedColumnName = "id", foreignKey = @ForeignKey(name = "role_settings_iam_role_FK"))
private RoleMaster roleId;
}
RoleMaster.java角色大师.java
@Entity @Table(name = "role")
@Getter @Setter @Data
public class RoleMaster implements Serializable {
private static final long serialVersionUID = 1792968151371176640L;
@Id
@GeneratedValue(generator = "uuid2")
@GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
private UUID id;
@Column(name = "name", nullable = false, length = 255)
private String name;
}
RoleSettingsRepository.java RoleSettingsRepository.java
public interface RoleSettingsRepository extends JpaRepository<RoleSettings, UUID>{}
RoleSettingsService.java角色设置服务.java
@Service
Class RoleSettingsService {
@Autowired
private RoleSettingsRepository roleSettingsRepository;
public BaseDTO create(RoleSettings roleSettings) {
BaseDTO response = new BaseDTO();
RoleSettings newRoleSettings = new RoleSettings();
try {
newRoleSettings.setRoleId(roleSettings.getRoleId());
newRoleSettings.setAppAccessId(roleSettings.getAppAccessId());
newRoleSettings.setCreate(roleSettings.getCreate());
newRoleSettings.setUpdate(roleSettings.getUpdate());
newRoleSettings.setRead(roleSettings.getRead());
newRoleSettings.setDelete(roleSettings.getDelete());
roleSettingsRepository.save(newRoleSettings);
response.setStatusCode(200);
} catch (Exception e) {
}
return response;
}
}
RoleSettingsController.java角色设置控制器.java
@RestController
@RequestMapping("/v1/rolesettings")
public class RoleSettingsController {
@Autowired
private RoleSettingsService roleSettingsService;
@PostMapping("/post")
public BaseDTO create(@RequestBody RoleSettings roleSettings) {
BaseDTO response = roleSettingsService.create(roleSettings);
return response;
}
}
my json object我的 json 对象
{ "roleId" :{"id": "b2e64c82-ab75-41d3-bb10-e9150f314807"} }
and my roleId is stored in database as type binary(16).我的 roleId 以 binary(16) 类型存储在数据库中。
Check in your database data type of the id
column.检查
id
列的数据库数据类型。 It has to be BINARY(16)
.它必须是
BINARY(16)
。 And annotate your entity field as:并将您的实体字段注释为:
@Id
@GeneratedValue(generator = "uuid2")
@GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator")
@Column(columnDefinition = "BINARY(16)")
private UUID id;
Note that you nned to add a column definition in this case.请注意,在这种情况下,您需要添加列定义。
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