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错误:对象无效作为React子代

[英]Error: Objects are not valid as a React Child

I want to display an object if the condition is false for which I was doing something like this in my stateful component return statement. 如果条件为false,我想显示一个对象,为此我在有状态组件return语句中执行了类似的操作。

{ !this.state.searchCoin ?   {displayCrypto}   : null }

For this, it is throwing the following error 为此,它引发以下错误

Objects are not valid as a React Child 对象无效作为React子代

My display crypto looks something like this (called in render) 我的显示密码看起来像这样(称为渲染)

let displayCrypto = CryptoData.map(el => {
    return (<CoinCard
       no={i++}
       key={el["short"]}
       coinShortName = {el["short"]}
       coinName = {el["long"]}
       coinPrice = {el["price"].toFixed(2)}
       marketCap = {(el["mktcap"]/1000000000).toFixed(4)}
       percentChange = {el["perc"].toFixed(2)}
       vwapData={el["vwapData"].toFixed(2)}
      />

[Question:] How can we I use itinerary expression to display on object if the condition is false? [问题:]如果条件为假,如何使用行程表达式在对象上显示?

Ps: If you are downvoting this question then please leave a comment as well so that I can improve my question as well. 附言:如果您对此问题不满意,请也发表评论,以便我也可以改善我的问题。

You are wrapping the cryptoCoinCard components in brackets this prompts the error. 您将cryptoCoinCard组件包装在方括号中,这将提示错误。

Remove the {} and it should work. 删除{} ,它应该可以工作。

{ !this.state.searchCoin ? displayCrypto : null }

Just remove the {} : { !this.state.searchCoin ? displayCrypto : null } 只需删除{}{ !this.state.searchCoin ? displayCrypto : null } { !this.state.searchCoin ? displayCrypto : null }

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