[英]Presto SQL: TO_UNIXTIME
I want to convert a readable timestamp to UNIX time.我想将可读时间戳转换为 UNIX 时间。
For example: I want to convert 2018-08-24 18:42:16
to 1535136136000
.例如:我想将
2018-08-24 18:42:16
转换为1535136136000
。
Here is my syntax:这是我的语法:
TO_UNIXTIME('2018-08-24 06:42:16') new_year_ut
My error is:我的错误是:
SYNTAX_ERROR: line 1:77: Unexpected parameters (varchar(19)) for function to_unixtime. Expected: to_unixtime(timestamp) , to_unixtime(timestamp with time zone)
You need to wrap the varchar in a CAST to timestamp:您需要将 varchar 包装在 CAST 到时间戳中:
to_unixtime(CAST('2018-08-24 06:42:16' AS timestamp)) -- note: returns a double
If your timestamp value doesn't have fraction of second (or you are not interested in it), you can cast to bigint to have integral result:如果您的时间戳值没有秒的小数部分(或者您对它不感兴趣),您可以转换为 bigint 以获得整数结果:
CAST(to_unixtime(CAST('2018-08-24 06:42:16' AS timestamp)) AS BIGINT)
If your readable timestamp value is a string in different format than the above, you would need to use date_parse
or parse_datetime
for the conversion.如果您的可读时间戳值是与上述格式不同的字符串,则需要使用
date_parse
或parse_datetime
进行转换。 See https://trino.io/docs/current/functions/datetime.html for more information.有关详细信息,请参阅https://trino.io/docs/current/functions/datetime.html 。
Note: when dealing with timestamp values, please keep in mind that: https://github.com/trinodb/trino/issues/37注意:在处理时间戳值时,请记住: https ://github.com/trinodb/trino/issues/37
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