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方法中的通用声明

[英]Generic declaration in method

What does the generic type declaration <T> right before the return type of the get method in the following code example mean? 在以下代码示例中,恰好在get方法的返回类型之前的泛型类型声明<T>是什么意思?

public interface Listener<T, R> {
    <T> Listener<T, R> get();
}

I understand its meaning in the class declaration of Listener but I did not find a practical example using <T> in that way for a method. 我在Listener的类声明中理解了它的含义,但没有找到以这种方式使用<T>的实际示例。

It is a method scoped parameterized type. 它是方法范围内的参数化类型。 It is defined only in the scope of the get() method and it hides the T declared in the Listener class. 它仅在get()方法的范围内定义,并且隐藏了在Listener类中声明的T
Hiding type is something to avoid and defining a method scoped parameterized type in a generic class is often questionable. 隐藏类型是要避免的事情,在泛型类中定义方法范围的参数化类型通常是有问题的。

I want to know what is the role of the parameter in that place. 我想知道该参数在那个地方的作用。

Here T is a type inferred by the client of the method. 这里T是由该方法的客户端推断出的类型。
But as this T is distinct of the T declared in the class, it can be a distinct type. 但是由于此T与类中声明的T不同,因此它可以是不同的类型。
If you want to convert the T of the generic class to another type specified by the client it could make sense. 如果要将泛型类的T转换为客户端指定的另一种类型,则可能有意义。 For example suppose the implementation : 例如,假设实现:

public class MyListener implements Listener<String, Integer>{

    @Override
    public <T> Listener<T, Integer> get() {
        return convert to T and return a new instance of Listener...;
    }

}

So you could write : 所以你可以这样写:

MyListener myListener = new MyListener();
Listener<Float, Integer> listener = myListener.get();

Note that the returned Listener and MyListener are not compatible types. 请注意,返回的ListenerMyListener不是兼容类型。


I would add that your interface is actually a functional interface as it declares a single abstract instance method. 我要补充一点,您的接口实际上是一个功能接口,因为它声明了一个抽象实例方法。
Using generic method doesn't allow to use functional interface with lambdas body but only with method references. 使用泛型方法不允许将函数接口与lambdas主体一起使用,而只能与方法引用一起使用。

For example these could not compile : 例如,这些无法编译:

Listener<String, Integer> invalidListener = () -> new MyListener<String, Integer>();
Listener<String, Integer> invalidListener2 = () -> new MyListener<>();

while the method reference will compile : 而方法参考将编译:

Listener<String, Integer> validListener = MyListener::new;

This is a method specific parametrized type, but... There is already defined T and R parameters in the interface so this should be avoided since it hides the defined parameter from the interface. 这是方法特定的参数化类型,但是...接口中已经定义了TR参数,因此应避免这种情况,因为它从接口隐藏了已定义的参数。

The correct usage example would be in the case the interface defines only parameter R : 正确的用法示例是接口仅定义参数R

public interface Listener<R> {
    <T> Listener<R> get(T t);
}

However, even this usage is questionable. 但是,即使这种用法也值得怀疑。 The example is clear - the interface works with parameter R and only its method uses T additionally. 这个例子很清楚-接口使用参数R并且仅其方法另外使用T Another method without this <T> singature would not be able to use T . 没有<T>特征的另一种方法将无法使用T

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