GraphQL解析器-承诺解决后返回我的函数

Question

I'm making a request to server to fetch some values and push them in an array

My GraphQL server's return me the array before the process ending, hence returns an empty array. Here a reproduction of the two methods I use :

1-

  var array= [];
        var auths= authModel.find({}).exec()
        .then(res => {

            res.map(el =>{ 
                array.push(el.ip)
            })
        }).then(() => array)

console.log(auths) // object Promise
console.log(array) // []

2-

  const auths= authModel.find().exec();
            if(!auths){ 
                throw new Error("Error while fetching users...")
            }
            console.log("auths:", auths) //  Promise { <pending> }
            return auths // on graphiql > "auths": { "ip": null }

What is going wrong ? How make my element returns when the promise is resolved ?

Any hint would be great, thanks

Answer 1

If you run something that returns a promise, the value can be referenced in the following parentheses eg

.then((data) => data)

Will return the data obtained from the promise.

If you want to do something locally with the returned data, like assign it to a local variable, you can do that within the then.

Alternately if you just need to return the data to the parent function that invoked this resolver function, then just add a return statement to the beginning of the authmodel.find statement as well.