SQL喜欢多条语句

Question

So I have the following query which does not give back the right results and I do not know why:

Sample data:

LIST1 | LIST2
APRIL | NOLA
NOLA  | BEBB
NOLA  | APROLS
APRA  | BLIN

The query:

SELECT LIST1, 
       LIST2, 
       CASE WHEN (([LIST1] LIKE '%APR%' 
                   OR [LIST1] LIKE '%NOLA%') 
             AND ([LIST2] NOT LIKE '%APR%' 
                   AND [LIST2] NOT LIKE '%NOLA%')) 
            THEN 1 
            ELSE 0 
       END AS RESULTS

It gives back 1 for both rows. It should give back 0 for the first row. So I would expect the following output

LIST1 | LIST2 | RESULTS
APRIL | NOLA  | 0
NOLA  | BEBB  | 1
NOLA  | APROLS| 0
APRA  | BLIN  | 1

What is my mistake here? The output should be 0 for those two cases as I have clearly put in an 'AND' statement.

Answer 1

SELECT LIST1, 
       LIST2, 
       CASE 
          WHEN (([LIST1] LIKE '%APR%' 
                 OR [LIST1] LIKE '%NOLA%') 
           OR ([LIST2] NOT LIKE '%APR%' 
                AND [LIST2] NOT LIKE '%NOLA%')) 
          THEN 1 
          ELSE 0 
       END AS RESULTS

LIST1   LIST2   RESULTS
APRIL   NOLA    1
NOLA    BEBB    1
NOLA    APROLS  1
APRA    BLIN    1

it gives you for both case 1 because [LIST1] LIKE '%APR%' OR [LIST1] LIKE '%NOLA%' this line is true for 'APRIL' of 1st row value of list1 and again it is true for 'NOLA' for 2nd row and when any portion of will true of or condition then full condition will be true. As a result you got both case 1

but if you put and condition then result will be as your expectation

SELECT LIST1, 
       LIST2, 
       CASE WHEN (
         (
           [LIST1] LIKE '%APR%' 
                   OR [LIST1] LIKE '%NOLA%') 
             AND 
         (
                  [LIST2] NOT LIKE '%APR%' 
                   AND [LIST2] NOT LIKE '%NOLA%')

          ) 
            THEN 1 
            ELSE 0 
       END AS RESULTS from t

http://sqlfiddle.com/#!18/9f8c5/1

LIST1   LIST2   RESULTS
APRIL   NOLA    0
NOLA    BEBB    1
NOLA    APROLS  0
APRA    BLIN    1