[英]Reading a text file content into a list of integers
I have a file containing: 我有一个文件包含:
1 3 3
1 5 6
2 4 9
2 4 8
4 5 7
and I want to read it into a list of list where: 我想将其读入列表列表,其中:
[[1,3,3],[1,5,6],[2,4,9],[2,4,8],[4,5,7]]
I tried: 我试过了:
def main():
filename = open("mytext.txt","r",encoding = "utf-8")
file = filename
lst = []
for line in file:
line = line.strip().split()
lst.append(line)
for val in range(len(lst)):
val = int(lst[val])
print(lst)
main()
but I'm getting an error saying 但我说错了
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'
Would appreciate some help on this. 希望对此有所帮助。
We can use numpy.genfromtxt
我们可以使用
numpy.genfromtxt
import numpy as np
answer = np.genfromtxt('Test.txt', dtype=np.int64).tolist()
Use list comprehensions and readlines
使用列表推导和
readlines
In [107]: with open('mytext.txt', encoding='utf-8') as file_pointer:
...: lst = [[int(j) for j in i.split()] for i in file_pointer.readlines()]
List comprehensions are often much faster and more readable than other methods. 列表理解通常比其他方法快得多并且可读性强。
The above method is similar to 上面的方法类似于
In [111]: with open('mytext.txt', encoding='utf-8') as file_pointer:
...: lst = []
...: for i in file_pointer.readlines():
...: inner_lst = []
...: for j in i.split():
...: inner_lst.append(int(j))
...:
...: lst.append(inner_lst)
...:
In [112]: lst
Out[112]: [[1, 3, 3], [1, 5, 6], [2, 4, 9], [2, 4, 8], [4, 5, 7]]
In your code, try replacing: 在您的代码中,尝试替换:
for val in range(len(lst)):
val = int(lst[val])
with: 与:
result = []
for row in lst:
row_list = []
for i in row.split():
val = int(i.strip())
row_list.append(var)
result.append(row_list)
or more succintly: 或更简洁地:
result = [[int(i.strip()) for i in row.split()] for row in lst]
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