PHP：如何检索 .gz 中包含的文件的文件名？

Question

My test.gz contains for instance : image1.jpg.我的 test.gz 包含例如：image1.jpg。

How can I decompress the test.gz so it gives me image1.jpg ?如何解压缩 test.gz 以便它给我 image1.jpg ？

I tried that method:我试过这种方法：

$file = gzopen($file_name, 'rb');
$out_file = fopen($out_file_name, 'wb');

but it supposes you need to know the filename contained in the .gz file但它假设您需要知道 .gz 文件中包含的文件名

regards问候

Answer 1

You need to use PHP PharData to extract and read its content.您需要使用 PHP PharData来提取和读取其内容。

To extract tar or tar.gz :提取tar或tar.gz ：

    $phar = new PharData('myphar.tar');
    $phar->extractTo('/full/path');

And to list all files, you can use :要列出所有文件，您可以使用：

archive = new PharData('/upload/directory/myphar.tar.gz');

foreach (new RecursiveIteratorIterator($archive) as $file) {
    echo $file . "<br />";
}