[英]std::void_t and nested non type members
I have the following code where I get unexpected result (second static_assert
fails): 我在以下代码中得到了意外的结果(第二个static_assert
失败):
#include <type_traits>
template <typename T, typename = void>
struct is_bananas : std::false_type {};
template <typename T>
struct is_bananas<T, std::void_t<typename T::config::num_items>>
: std::true_type {};
struct Config{
static constexpr int num_items=42;
};
struct Bananas{
using config = Config;
};
static_assert(is_bananas<int>::value == false);
static_assert(is_bananas<Bananas>::value == true);
When I use T::config
instead of T::config::num_items
code works as expected. 当我使用T::config
而不是T::config::num_items
代码将按预期工作。
If I use decltype
around num_items
then it works. 如果我在num_items
周围使用decltype
,那么它将起作用。
Am I correct to assume that void_t
only works with types? 我是否可以正确地假设void_t
仅适用于类型?
Is there a nicer way to do what I want? 有没有更好的方法来做我想要的?
If somebody is confused by this(and think: just throw a decltype
) - I find decltype
hard to read in real code when there are long names and deep nesting so if there is a nicer way to do this with void_t
or any other template code I would like to know. 如果有人对此感到困惑(并认为:仅仅抛出一个decltype
)-我发现在长名称和深层嵌套的情况下,很难在真实代码中读取decltype
,因此,如果有更好的方法可以使用void_t
或任何其他模板代码来执行此操作我想知道。
Is there a nicer way to do what I want? 有没有更好的方法来做我想要的?
Nice and nicer are subjective. 好和好是主观的。
By example, I find very nice your decltype()
solution. 通过示例,我发现您的decltype()
解决方案非常好。
Anyway... a possible alternative is define a substitute for std::void_t
that works with value types 无论如何...一个可能的替代方法是定义可与值类型一起使用的std::void_t
的替代品
Something as 像
template <auto...>
using value_void_t = void;
and write 和写
template <typename T>
struct is_bananas<T, value_void_t<T::config::num_items>>
: std::true_type {};
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.