确定最高价值的变量并使用python random打印变量的名称

Question

I've got this problem while i was making a project where i got 3 random generated numbers and want to determine the highest number and then using it's variable name and print out something like this:

print("the winner is:", winner, "with", winners_score, "points")

the "winner" is the teams name and the "points is the amount of points it had. I tried multiple ways to solve this problem including making a list and determining the highest score, etc. But i couldn't print the winner's name, only the winner's score. I then tried a dictionary with the name as key and the score as value and then the other way around. They both didn't work, i then tried .values() and .keys() but also didn't work. I finally created a piece of code to solve it but was too complex to use in a program with more than 10 variables. Here's the code of that test:

from random import *
score1 = randint(0, 51)
score2 = randint(0, 51)
score3 = randint(0, 51)

print(score1)
print(score2)
print(score3)
lister = [score1, score2, score3]
highest_score = max(lister)
winner = " "
if score1 > score2 and score1 > score3:
    winner = "score1"
elif score2 > score1 and score2 > score3:
    winner = "score2"
elif score3 > score1 and score3 > score2:
    winner = "score3"
else:
    winner = "nobody"
print("the highest score is", highest_score, "by", winner)

but this wouldn't work if i has a draw between the first two places. So how do i get the highest score and the winner with that score with a short(er) line of code PS. I have also checked other questions on this website but both questions didn't give me the wanted answer, to read those: Finding The Biggest Key In A Python Dictionary and Python: finding which variable has the highest value and assign that value to a new variable . thank you for your help!

Answer 1

You can create a list of all according winner names to each score, then create list of all indices with the highest score and then create a list of all winners.

lister = [score1, score2, score3]
list_of_according_winner = ["score1", "score2", "score3"]

# list of highscore indices (if two are equal, you can have several elements)
highscore_index = [i for i, x in enumerate(lister) if x == max(lister)]

# create list of winners
winners = [list_of_according_winner[i] for i in highscore_index]

#printing
print("the highest score is", max(lister), "by", ", ".join(winners))

I omitted the option "nobody", as max(lister) will always have a value and therefore there will be always a winner, at least in the way as you implemented it.

Answer 2

You can use a dictionary to store the name and score, this keeps those two bits of associated data together. Use the built-in sorted function to get the highest score first, comparing the first two scores to check if there was a drawer.

from random import randint

l = []

def addTeam(name):
    l.append(
    {"name": name, "score": randint(0, 51)}
    )

def sortScores():
    return sorted(l, key=lambda t: t["score"], reverse=True)

def isDraw():
    if l[0]["score"] == l[1]["score"]:
        return True
    return False

if __name__ == '__main__':
    addTeam("Team1")
    addTeam("Team2")
    addTeam("Team3")
    l = sortScores()

    if isDraw():
        winner = "nobody"
    else:
        winner = l[0]["name"]

    print("The highest score is {} by: {}".format(l[0]["score"], winner))

Try to avoid doing * imports, as this can lead to conflicts.