如果元素在另一个对象数组中，则删除包含对象数组内部数组的对象属性

Question

I am working with a large array of objects. I have simplified my data structure to the following. Each object has an id and each id has anywhere from 0 to 4 arrays associated with it. The array names are dynamically generated and will have at most 2 elements, and can be any number of names based on other requirements. My initial object looks like this:

const arr = [{id: "12345", array1: ["Banana", "Apple"], array2: ["Orange", "Strawberry"]}, 
             {id: "12345", array0: ["Potato", "Tomato"]},           
             {id: "54321", array0: ["Kiwi", "Apple"], array1: ["Potato", "Onion"]},
             {id: "54321", array2: ["Orange", "Tomato"], array0: ["Kiwi", "Banana"]},
             {id: "13579", array1: ["Banana", "Apple"], array2: ["Grapefruit", "Onion"]},
             {id: "13579", array1: ["Potato", "Banana"], array2: ["Orange", "Pepper"]}]

I have a "lookup" array of objects. Each object has an id and a type

const lookup = [{id: "12345", type: "Banana"},
                {id: "12345", type: "Kiwi"},
                {id: "12345", type: "Apple"},
                {id: "54321", type: "Strawberry"} 
                {id: "54321", type: "Tomato"},
                {id: "54321", type: "Banana"},
                {id: "13579", type: "Tomato"},
                {id: "13579", type: "Grapefruit"}]

I need to use the "lookup" object for any matching id that has a type that is in any of the corresponding id's arrays. I need to remove that property from the object. Lookups should be 1:1, So my resulting array of objects would look something like so

const result = [{id: "12345", array2: ["Orange", "Strawberry"]}, 
                {id: "12345", array0: ["Potato", "Tomato"]},           
                {id: "54321", array0: ["Kiwi", "Apple"], array1: ["Potato", "Onion"]},
                {id: "54321"},
                {id: "13579", array1: ["Banana", "Apple"]},
                {id: "13579", array1: ["Potato", "Banana"], array2: ["Orange", "Pepper"]}]

The part I am getting hung up on is not knowing the object key name ahead of time, and also how to search the object entries for that key with the lookup object's type property. My initial thought was to use Object.values but then I am not sure how to remove the object property if I use that.

Answer 1

For each object in the lookup check if the id matches in the arr array. If matches then get all the keys from that specific object in arr array using Object.keys.

pseudo code

1. If id matches in both the array then take that object from the arr array.

2. Use Object.keys to get array of keys For example the array will be now

   ['id','array0','array1']

3. Now iterate this array and & use the element from this array as key name & check if the value is an array again. For example

    `{id: "12345", array1: ["Banana", "Apple"], array2: ["Orange", "Strawberry"] }['array0']` 

   will produce ["Banana", "Apple"] . In this check if the type exist using indexOf , If not then use delete to delete the key and value from the object

 const arr = [{ id: "12345", array1: ["Banana", "Apple"], array2: ["Orange", "Strawberry"] }, { id: "12345", array0: ["Potato", "Tomato"] }, { id: "54321", array0: ["Kiwi", "Apple"], array1: ["Potato", "Onion"] }, { id: "54321", array2: ["Orange", "Tomato"], array0: ["Kiwi", "Banana"] }, { id: "13579", array1: ["Banana", "Apple"], array2: ["Grapefruit", "Onion"] }, { id: "13579", array1: ["Potato", "Banana"], array2: ["Orange", "Pepper"] } ] const lookup = [{ id: "12345", type: "Banana" }, { id: "12345", type: "Kiwi" }, { id: "12345", type: "Apple" }, { id: "54321", type: "Strawberry" }, { id: "54321", type: "Tomato" }, { id: "54321", type: "Banana" }, { id: "13579", type: "Tomato" }, { id: "13579", type: "Grapefruit" } ] let newArray = []; lookup.forEach(function(item, index) { arr.forEach(function(arrId, index1) { if (item.id === arrId.id) { Object.keys(arrId).forEach(function(elem) { if (Array.isArray(arrId[elem]) && arrId[elem].indexOf(item.type) !== -1) { delete arr[index1][elem] } }) } }) }) console.log(arr) 

Note: Mutating an array inside loop is not a good idea