<String.h>我对strncpy的实现对吗？

Question

  char  *strncpy(char *dest, char *src, unsigned int n)
{
    unsigned int a;
    a = 0;
    while (src[a] && a < n)
    {
        dest[a] = src[a];
        a++;
    }
    while (a < n)//if src not bigger than n should I put '\0' at the end of dest ?
    {
        dest[a] = '\0';
        a++;
    }
    dest[a] = '\0';
    return (dest);
}

Hello Stackoverflow

I am looking for my mistake, I know that when n > strlen(dest), it does abort on the real strncpy and I am wondering why it is wrong ? Thanks for your help

Answer 1

You no need to append '\\0' continuously, if you want to rest of the memory of dest to be filled with zeros you can use calloc() while allocating memory

char  *strnncpy(char *dest, char *src, unsigned int n)
{
    unsigned int a;
    a = 0;
    while ( src[a] && a < n)
    {
        dest[a] = src[a];
        a++;
    }
    dest[a] = '\0';
    return (dest);
}