Python：在复杂方程中使用 math.sqrt 函数

Question

I am trying to write code to solve this python exercise: I must use the 'math' library, sqrt and possibly pow functions.

"The distance between two points x and y is the square root of the sum of squared differences along each dimension of x and y.

"Create a function that takes two vectors and outputs the distance between them.

x = (0,0) y = (1,1)"

So far I've tried this - which certainly hasn't worked.

x = (0,0)
y = (1,1)
(c1, c2) = x
(c3, c4) = y
math.sqrt(sum((c1,**2)(c2,**2)(c3,**2)(c4,**2)))

 File "<ipython-input-14-ac0f3dc1fdeb>", line 1 math.sqrt(sum((c1,**2)(c2,**2)(c3,**2)(c4,**2))) ^ SyntaxError: invalid syntax

if c1 < c3:
    difference1 = c3-c1
    print(difference1)

1

... not even sure if that's the kind of calculation I should be working with.

def distance(x, y):

ummm... I expect the function starts by unpacking the tuples, But not sure how to write the rest of it. or cleanly.

I'm a beginner programmer & not a mathematician so I may be wrong in more than one sense... This exercise is from this HarvardX course: 'Using Python for Research' .

It's OK to search for solutions via StackOverflow for learning on this course... not cheating to ask for pointers.

Many thanks for any ideas. I will keep searching around.

Answer 1

import math
def distance (x,y):
    value= math.sqrt ((x[0]-y[0])**2 + (x[1] - y[1])**2)
    print (value)
distance((0,0), (1,1))

Answer 2

Thanks so much for those ideas. I figured it out. So happy.

for (a,b) in x,y:
    dis = math.sqrt((y[0] - x[0])**2 + (y[1] - x[1])**2)
    print(dis)

Answer 3

import math
def distance(x1,x2,y1,y2):

    x=(x1,x2)
    y=(y1,y2)
    dis = math.sqrt((x[1]-x[0])**2 + (y[1] - y[0])**2)
    return dis

print(dis(0,0,1,1))

this works very well to answer your quest