[英]how to create a Codeigniter route
I have a CodeIgniter website and the link structure for the inner pages look like below: 我有一个CodeIgniter网站,内页的链接结构如下所示:
http://www.example.com/pages/Campus-Tour/18/3 http://www.example.com/pages/Campus-Tour/18/3
pages is my controller name and campus-tour, 18 and 3 are the values passed into the index method. pages是我的控制器名称,campus-tour是18和3是传递到index方法中的值。
I want to make a pretty url, so can I use something like this in routes.php? 我想创建一个漂亮的网址,因此可以在routes.php中使用类似的内容吗?
$route['campus-life/campus-tour'] = 'pages/Campus-Tour/18/3';
to show this URL " http://www.example.com/campus-life/campus-tour " 显示此网址“ http://www.example.com/campus-life/campus-tour ”
Please use this syntax for routing. 请使用此语法进行路由。
$route['string-that-you-want-to-show-in-url'] = 'controller/function/arg1/arg2';
Example -- 例子-
$route['campus-life/campus-tour'] = 'pages/campus_tour/$1/$2';
Note:- PHP doesn't support hyphen(-) inside function name, your function name (Campus-Tour) is invalid, please check it & use the above syntax. 注意:-PHP在函数名称中不支持连字符(-),您的函数名称(Campus-Tour)无效,请检查它并使用上面的语法。
FYI: A valid function name starts with a letter or underscore , followed by any number of letters, numbers, or underscores.
仅供参考:有效的函数名称以字母或下划线开头 , 后跟任意数量的字母,数字或下划线。
If you transmit data URL with this to pages/Campus-Tour/18/3
this campus-life/campus-tour
it's clearly missing your URL parameter as you can see. 如果您将与此相关的数据URL传输到
pages/Campus-Tour/18/3
此campus-life/campus-tour
则显然会丢失您的URL参数。
What you can do is <form>
submit with POST
and in the function, you can catch those. 您可以做的是
<form>
用POST
提交,在函数中,您可以捕获这些内容。
In View 视野中
<form action ="campus-life/campus-tour" method ="post">
<input type="hidden" name="first_param" value = "18"/>
<input type="hidden" name="second_param" value = "3"/>
<input type="submit"> # make this a No button. Should looks like <a> tag. Use CSS. (check Link)
</form>
In Controller 在控制器中
function Name() #add valid function/controller name
{
# catch the POST values
}
Reference : How to make a button look like a link? 参考: 如何使按钮看起来像链接?
Following is the syntax for routing. 以下是路由的语法。 Please use this:
请使用此:
$route['pages/Campus-Tour/(:any)/(:any)'] = 'pages/campus-tour/$1/$2';
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